我正在尝试更新数组数组中的值,但是我猜for item in buffer
必须在缓冲区中复制该项目,而不是提供对原始项目的引用。除了某种for i=...{buffer[i][3]='Moved'}
之外,还有其他方法可以这样做。
var buffer = [[String]]()
let bufRemoved = buffer.filter({$0[3] == "Removal"})
let bufAdded = buffer.filter({$0[3] == "Addition"})
let moved = bufRemoved.filter({item in bufAdded.contains(where: {$0[2] == item[2]})})
for var item in buffer {
if moved.contains(where: {$0[2] == item[2]}) {
switch item[3] {
case "Removal":
item[3] = "Moved(out)"
case "Addition":
item[3] = "Moved(in)"
default:
break
}
}
}
let bufMoved = buffer.filter({$0[3].contains("Move")})
答案 0 :(得分:1)
一种解决方案是让enumerate
数组也具有索引
for (index, item) in buffer.enumerated() {
if moved.contains(where: {$0[2] == item[2]}) {
switch item[3] {
case "Removal":
buffer[index][3] = "Moved(out)"
case "Addition":
buffer[index][3] = "Moved(in)"
default:
break
}
}
}