使用data.frame展平嵌套列表

Question

我有两个维度的嵌套列表。每个元素都是data.frame。我想将其展平到一个维度

让我们举个例子。 order by (case when right(binlocation) in ('A', 'B', 'C', 'D' then 1 else 2 end), left(binlocation, 1), len(binlocation), binlocation 是嵌套列表。每个元素都有两个data.frames。因此它是[[2]] * [[2]]嵌套列表。

given

我想将其展平为一个维度，因此它将是一个包含4个元素的列表，每个元素都是data.frame。结果将是...

given<-replicate(2,list(data.frame(unlist(replicate(10,sample(c(0.2,0.3,0.4,0.1),2,replace=FALSE),simplify=FALSE)),ncol=2)))
colnames(given[[1]])<-c('a','b')
colnames(given[[2]])<-c('a','b')
nested<-list(given, given)
nested

[[1]]
[[1]][[1]]
        a   b
 [1,] 0.3 0.3
 [2,] 0.2 0.4
 [3,] 0.1 0.2
 [4,] 0.3 0.3
 [5,] 0.3 0.4
 [6,] 0.1 0.2
 [7,] 0.3 0.4
 [8,] 0.2 0.3
 [9,] 0.1 0.3
[10,] 0.3 0.4

[[1]][[2]]
        a   b
 [1,] 0.3 0.2
 [2,] 0.4 0.4
 [3,] 0.2 0.4
 [4,] 0.4 0.1
 [5,] 0.1 0.4
 [6,] 0.4 0.3
 [7,] 0.1 0.4
 [8,] 0.4 0.2
 [9,] 0.2 0.4
[10,] 0.4 0.2

[[2]]
[[2]][[1]]
        a   b
 [1,] 0.3 0.3
 [2,] 0.2 0.4
 [3,] 0.1 0.2
 [4,] 0.3 0.3
 [5,] 0.3 0.4
 [6,] 0.1 0.2
 [7,] 0.3 0.4
 [8,] 0.2 0.3
 [9,] 0.1 0.3
[10,] 0.3 0.4

[[2]][[2]]
        a   b
 [1,] 0.3 0.2
 [2,] 0.4 0.4
 [3,] 0.2 0.4
 [4,] 0.4 0.1
 [5,] 0.1 0.4
 [6,] 0.4 0.3
 [7,] 0.1 0.4
 [8,] 0.4 0.2
 [9,] 0.2 0.4
[10,] 0.4 0.2

我尝试了[[1]] a b [1,] 0.3 0.3 [2,] 0.2 0.4 [3,] 0.1 0.2 [4,] 0.3 0.3 [5,] 0.3 0.4 [6,] 0.1 0.2 [7,] 0.3 0.4 [8,] 0.2 0.3 [9,] 0.1 0.3 [10,] 0.3 0.4 [[2]] a b [1,] 0.3 0.2 [2,] 0.4 0.4 [3,] 0.2 0.4 [4,] 0.4 0.1 [5,] 0.1 0.4 [6,] 0.4 0.3 [7,] 0.1 0.4 [8,] 0.4 0.2 [9,] 0.2 0.4 [10,] 0.4 0.2 [[3]] a b [1,] 0.3 0.3 [2,] 0.2 0.4 [3,] 0.1 0.2 [4,] 0.3 0.3 [5,] 0.3 0.4 [6,] 0.1 0.2 [7,] 0.3 0.4 [8,] 0.2 0.3 [9,] 0.1 0.3 [10,] 0.3 0.4 [[4]] a b [1,] 0.3 0.2 [2,] 0.4 0.4 [3,] 0.2 0.4 [4,] 0.4 0.1 [5,] 0.1 0.4 [6,] 0.4 0.3 [7,] 0.1 0.4 [8,] 0.4 0.2 [9,] 0.2 0.4 [10,] 0.4 0.2 程序包的rlist函数，但是没有用。它打印出了变量的名称，而其他功能（例如list.flatten也不起作用。

非常感谢您的帮助。