Question

我有以下MySQL查询，该查询显示了按周分组的新用户数。

这是查询：

SELECT  floor(datediff(u.created_at, curdate()) / 7) AS weeks_ago,
        count(DISTINCT u.id) AS "New Users in Week"
FROM users u 
GROUP BY weeks_ago
ORDER BY weeks_ago DESC;

这将输出：

weeks_ago | New Users in Week
0 | 100
1 | 120
2 | 50

如何添加显示日期范围的列，例如，如果今天运行（2019/07/16）

weeks_ago | date range | New Users in Week
0 | 2019/07/14 - 2019/07/20 | 100
1 | 2019/07/7 - 2019/07/13  | 120
2 | 2019/06/30 - 2019/07/6 | 50
.....

Answer 1

两列的最小日期和最大日期如何？

SELECT floor(datediff(u.created_at, curdate()) / 7) AS weeks_ago,
       date(min(u.created_at)), date(max(u.created_at))
       count(DISTINCT u.id) AS "New Users in Week"
FROM users u 
GROUP BY weeks_ago
ORDER BY weeks_ago DESC;

给定MySQL datediff，如何输出使用中的实际日期范围

1 个答案: