Question

当用户单击此按钮时，意味着要单击将更新数据库的void方法，因此我们知道已单击它。但是，每次单击该按钮时，它将使用户超链接到另一个页面（试图将用户带到asp-action）。我如何才能停止超链接？因此，当用户单击该按钮时，他们不会看到任何更改，但是会调用该方法。

<button type="button" asp-action="xxx" asp-controller="xxx" class="btn btn-primary">

Answer 1

我认为您可能会把事情混在一起。

from __future__ import division, print_function, absolute_import import tflearn from tflearn.layers.core import input_data, dropout, fully_connected from tflearn.layers.conv import conv_2d, max_pool_2d from tflearn.layers.normalization import local_response_normalization from tflearn.layers.estimator import regression from data_utils import * import os from PIL import Image from numpy import array def res_image(f, image_shape=[224,224], grayscale=False, normalize=True): img = load_image(f) width, height = img.size if width != image_shape[0] or height != image_shape[1]: img = resize_image(img, image_shape[0], image_shape[1]) if grayscale: img = convert_color(img, 'L') elif img.mode == 'L': img = convert_color(img, 'RGB') img = pil_to_nparray(img) if normalize: # << this here is what you need img /= 255. img = array(img).reshape(1, image_shape[0], image_shape[1], 3) return img # Building the network network = input_data(shape=[None, 227, 227, 3]) network = conv_2d(network, 96, 11, strides=4, activation='relu') network = max_pool_2d(network, 3, strides=2) network = local_response_normalization(network) network = conv_2d(network, 256, 5, activation='relu') network = max_pool_2d(network, 3, strides=2) network = local_response_normalization(network) network = conv_2d(network, 384, 3, activation='relu') network = conv_2d(network, 384, 3, activation='relu') network = conv_2d(network, 256, 3, activation='relu') network = max_pool_2d(network, 3, strides=2) network = local_response_normalization(network) network = fully_connected(network, 4096, activation='tanh') network = dropout(network, 0.5) network = fully_connected(network, 4096, activation='tanh') network = dropout(network, 0.5) network = fully_connected(network, 2, activation='softmax') # output is the number of outcomes network = regression(network, optimizer='momentum', loss='categorical_crossentropy', learning_rate=0.001) # Training model = tflearn.DNN(network, tensorboard_dir=R'C:\Users\b0588718\Source\Repos\AlexNet\AlexNet') model.load('model.tfl') f = r'C:\Users\b0588718\Source\Repos\AlexNet\AlexNet\rawdata\jpg\0\P1170047.jpg' img = res_image(f, [227,227], grayscale=False, normalize=True) pred = model.predict(img) print(" %s" % pred[0])标记不会重定向到任何地方，除非其类型为<button>并且位于submit标记内：

<form>

<form method="post" action="/foo"> <button type="submit">Send</button> </form>标签在使用正确的网址声明时将在点击时重定向：

<a>

可以使用Tag Helpers来构造：

<a href="/Home/Privacy">Privacy</a>

<a asp-controller="Home" asp-action="Privacy">Privacy</a>标签和<button>标签都不是自动关闭标签。此类标签需要使用结束标签关闭：

<a>

如果不重新加载没有用于处理请求发送的客户端脚本的页面，则将无法发送 HTTP GET 请求。当您单击页面上的链接时，浏览器将处理发送的请求，但这意味着页面重新加载（我在这里谈论的是纯HTML页面，没有SPA）。如果您不希望重新加载页面，则必须处理自己发送的请求。换句话说-从客户端脚本发送 HTTP 请求。

您可以使用<button type="button">Foo</button>来实现：

jQuery

或纯JavaScript：

$('#updateDatabaseButton').click(function (e) {
    $.get($(e.target).attr('formaction'), function (data) {
        console.log(data);
    });
});

最终，通过设置const updateButon = document.getElementById('updateDatabaseButton'); updateButon.onclick = function () { var url = updateButon.getAttribute('formaction'); var http = new XMLHttpRequest(); http.open("GET", url); http.send(); http.onreadystatechange = (e) => { console.log(http.responseText) } };将您的按钮链接到客户端脚本：

id

停止操作按钮超链接

1 个答案: