Question

我有一个字符串text = "Fix me a meeting in 2 days"。我列出了一些单词meetingStrings。 "meet"中有meetingStrings。因此，我必须通过开会来拆分文本。

所需的输出：

2天之内

meetingStrings = [
    "appointment",
    "meet",
    "interview"
]
text = "Fix me a meeting in 2 days"
for x in meetingStrings:
    if x in text.lower(): 
        txt = text.split(x, 1)[1]
        print(txt)

这将提供输出：

在2天之内。

Answer 1

使用re.split()：

import re

meetingStrings = [
    "appointment",
    "meet",
    "interview"
]

text = "Fix me a meeting in 2 days"

print(re.split('|'.join(r'(?:\b\w*'+re.escape(w)+r'\w*\b)' for w in meetingStrings), text, 1)[-1])

打印：

 in 2 days

Answer 2

对您的代码稍作更改：

meetingStrings = [
    "appointment",
    "meet",
    "interview"
]
text = "Fix me a meeting in 2 days"
for x in meetingStrings:
    if x in text.lower():
        txt = text.split(x, 1)[1]
        print(txt.split(" ", 1)[1]) #<--- Here

只需获取最终输出，并在第一次出现空格时进行分割

Answer 3

此表达式也可以与i标志一起使用：

(?:meet|interview|appointment)\S*\s+((?:in|after)\s[0-9]+\s+(?:days?|months?|weeks?|years?))

，我们可以使用逻辑OR将所有想要的单词包含在非捕获组中，例如：

(?:in|after|on|from)

(?:days?|months?|weeks?|years?|hours?)

(?:meet|interview|appointment|session|schedule)

测试

import re

regex = r"(?:meet|interview|appointment)\S*\s+((?:in|after)\s[0-9]+\s+(?:days?|months?|weeks?|years?))"
test_str = "Fix me a meeting in 2 days meetings in 2 months meet in 1 week nomeeting in 2 days meet after 2 days"

print(re.findall(regex, test_str, re.IGNORECASE))

输出

['in 2 days', 'in 2 months', 'in 1 week', 'in 2 days', 'after 2 days']

如果要浏览/简化/修改该表达式，请在this demo的右上角进行解释。

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jex.im可视化正则表达式：

Answer 4

用于搜索。
您需要做的就是将文字放在单词的中间
然后匹配单词。

结果在捕获组1中。

无空格修饰

\b\w*(?:appointment|meet|interview)\w*\b(.*)

https://regex101.com/r/lK4zRz/1

可读版本

 \b 
 \w* 
 (?:
      appointment
   |  meet
   |  interview
 )
 \w* 
 \b 
 ( .* )                        # (1)

带有空格修剪

(?m)\b\w*(?:appointment|meet|interview)\w*\b[^\S\r\n]*(.*?)[^\S\r\n]*$

https://regex101.com/r/v2qAOQ/1

另外，如果您在任一正则表达式的开头添加.*，
它将始终获得最后一个关键字。

Answer 5

尝试一下：

import re
text = "Fix me a meeting in 2 days"
print(re.split("({})\\w*".format("|".join(meetingStrings)), text)[-1].strip())

输出：in 2 days

Answer 6

没有正则表达式， str.partition -

for x in meetingStrings: 
    pre, _, post = text.lower().partition(x) 
    if post: 
        pre = pre.rpartition(' ')[0] if not pre.endswith(' ') else pre.rstrip() 
        post = post.partition(' ')[-1] if not post.startswith(' ') else post.lstrip() 
        print([pre, post])

示例：

In [35]: meetingStrings = [ 
    ...:     "appointment", 
    ...:     "meet", 
    ...:     "interview" 
    ...: ] 
    ...: text = "Fix me a meeting in 2 days" 

    ...: for x in meetingStrings: 
    ...:     pre, _, post = text.lower().partition(x) 
    ...:     if post: 
    ...:         pre = pre.rpartition(' ')[0] if not pre.endswith(' ') else pre.rstrip() 
    ...:         post = post.partition(' ')[-1] if not post.startswith(' ') else post.lstrip() 
    ...:         print([pre, post]) 
    ...:                                                                                                                                                                                                    
['fix me a', 'in 2 days']

Answer 7

尝试这样的事情：

import re

meetingStrings = [
        "appointment",
        "meet",
        "interview"
]
text = "Fix me a meeting in 2 days"

def split_string(text, strings):
    search = re.compile('|'.join(strings))
    start = None
    input = text.split()
    for e, x in enumerate(input):
        if search.search(x):
            if start < e:
                yield ' '.join(input[start:e])
            start = None
        else:
            if start is None:
                start = e
    else:
        if start is not None:
            yield ' '.join(input[start:])

print(' '.join(split_string(text, meetingStrings)))

这可能比其他答案更长，但似乎确实做到了完全您想要的-拆分字符串，其中包含传入的字符串之一作为子字符串。

Answer 8

我有另一种更简单的方法，首先将句子中的所有单词分开，然后从出现meetingStrings的位置处切掉句子：

l=text.split()
for i in meetingStrings:
    for idx, j in enumerate(l):
        if i in j:
            l=l[idx+1:] 
print(' '.join(l))

礼物：

'in 2 days'

Answer 9

您可以只使用find（）和列表切片：

text = "Fix me a meeting in 2 days"
meetingStrings = [
    "appointment",
    "meet",
    "interview"
]


sep = [i for i in meetingStrings if i in text]

idx = text.find(sep[0])
idx_ = text[idx:].find(' ')
print (text[idx+idx_:])

输出：

in 2 days

Python：使用包含子字符串的单词拆分字符串

9 个答案:

测试

输出

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