Question

问题：有两列。 column1和column2 第1列可能有一些类似的数据（任务），而第2列则根据用户是否分配给该任务的结果为true和false。

我想按值分组，看看是否在同一任务（第1列）中甚至有1个假，然后也将其他类似的任务也假。

有人可以帮我吗？

Value	                              |PrimaryOwnerId
_______________________________________________________________________
EVP-RP&P	                          |  true
Execution Coordinator	                  |  true
Execution Coordinator	                  |  flase
Inspection Lead	                          |  true
Instrument, Electrical, and Analyzer      |  true
Logistics	                          |  true
Logistics	                          |  flase
Operations	                          |  true
Planning	                          |  true

我正在使用此查询。

   select CraftName AS value,
case 
   when PrimaryOwnerID is Null 
       Then 'true'
       else 'flase'
       End as PrimaryOwnerID
        FROM EventTasks AS et
                          INNER JOIN EventMileStones AS em ON em.EventMileStoneID = et.EventMileStoneID
                          INNER JOIN LocationTasks AS lt ON lt.LocationTaskID = et.LocationTaskID
                          INNER JOIN Crafts AS c ON c.ID = lt.CraftID
                     WHERE ProjectID = 4
                     group by CraftName, PrimaryOwnerID

Answer 1

对查询使用CTE，然后使用EXISTS检查值是否存在不为null的PrimaryOwnerID：

with cte as (
  select 
    CraftName AS value,
    PrimaryOwnerID,
  FROM EventTasks AS et
  INNER JOIN EventMileStones AS em ON em.EventMileStoneID = et.EventMileStoneID
  INNER JOIN LocationTasks AS lt ON lt.LocationTaskID = et.LocationTaskID
  INNER JOIN Crafts AS c ON c.ID = lt.CraftID
  WHERE ProjectID = 4
  GROUP BY CraftName, PrimaryOwnerID
)
select 
  c.value,
  case 
    when exists (
      select 1 from cte where value = c.value and PrimaryOwnerID is not null
    ) then 'false'
    else 'true'
  end PrimaryOwnerID
from cte c

Answer 2

我认为窗口函数更简单。因为您使用的是字符串，所以min()符合您的逻辑：

select CraftName AS value,
       min(PrimaryOwnerID) over (partition by CraftName) as new_PrimaryOwnerID
from EventTasks et join
     EventMileStones em 
     on em.EventMileStoneID = et.EventMileStoneID join
     LocationTasks lt 
     on lt.LocationTaskID = et.LocationTaskID join
     Crafts c 
     on c.ID = lt.CraftID
where ProjectID = 4
group by CraftName, PrimaryOwnerID;

不需要子查询或CTE。

分组并更改数据

2 个答案: