Question

我想在Java上问一些问题。我有从JSON数据解析的时间（字符串）列表。我需要找到哪个时间更接近系统时间。这样，现在时间是16:40。我的时间清单包含 “ 16:32”，“ 16:38”，“ 16:44”，“ 16:50”等。对于16:40，16:38比16:44更近，我需要找到它。我试图获取当前索引和下一个索引，解析它们并初始化新的日历等等。但是我不知道下一步该怎么做。

任何解决此问题的方法？

       String returnTime = current.getDonus();
        if (i < list.size() + 1) {
            TimeList nextOne=list.get(i+1);
            String nextReturnTime = nextOne.getDonus();
            String[] parsedNextReturn = nextReturnTime.split(":");
            String[] parsedReturn = returnTime.split(":");

            Date date = new Date();

            Calendar calNextReturn= Calendar.getInstance();
            calNextReturn.setTime(date);
            calNextReturn.set(Calendar.HOUR_OF_DAY, Integer.parseInt(parsedNextReturn[0]));
            calNextReturn.set(Calendar.MINUTE, Integer.parseInt(parsedNextReturn[1]));
            calNextReturn.set(Calendar.SECOND, 0);
            calNextReturn.set(Calendar.MILLISECOND, 0);

            Calendar calCurrentReturn= Calendar.getInstance();
            calCurrentReturn.setTime(date);
            calCurrentReturn.set(Calendar.HOUR_OF_DAY, Integer.parseInt(parsedReturn[0]));
            calCurrentReturn.set(Calendar.MINUTE, Integer.parseInt(parsedReturn[1]));
            calCurrentReturn.set(Calendar.SECOND, 0);
            calCurrentReturn.set(Calendar.MILLISECOND, 0);

            Calendar calSystem = Calendar.getInstance();
            calSystem.setTime(date);
            calSystem.set(Calendar.SECOND, 0);
            calSystem.set(Calendar.MILLISECOND, 0);
        }

Answer 1

尝试一下：

        long smallestABS = Long.MAX_VALUE;
        long systemTime = System.currentTimeMillis();
        long timeClosest;
        for (long time : timeList) {
            long abs = Math.abs(systemTime - time);
            if(smallestABS > abs){
                smallestABS = abs;                
                timeClosest = time;
            }
        }

找出两次之间的更近时间

1 个答案: