Question

我想按常规顺序记录日志

（通话1，通话2，通话3）

但是结果.. call2，call3，call1 ...

我该怎么办？

我用了promise ..但是结果是一样的.. 这是一些代码

{
..
if (typeof files['images1'] !== 'undefined' && files['images1'].length > 0) {
        convertToWebp(files['images1'])
        console.log(2)

    }
if (typeof files['images2'] !== 'undefined' && files['images2'].length > 0) {
        convertToWebp(files['images2'])
        console.log(2)

    }
    console.log(3)

    res.send~
}

async function convertToWebp(files :  MulterFile[]){
    files.forEach(async function(file) {
        await sharp(file.path).webp({quality:70}).toFile("some_rule", async (err, info) => { 
            await deleteFile(file.filename)
            console.log(1)
         }) 
    })
/*
await Promise.all(files.map(async (file) => {
    await sharp(file.path).webp({quality:70}).toFile("some_rule",  async (err, info) => { 
        await deleteFile(file.filename)
        console.log(1)
         }) 
      }))
*/
 }

function deleteFile(image : string){
    ..
}

Answer 1

尝试一下

async function convertToWebp(files :  MulterFile[]) {
 await Promise.all(files.map(async(file) => {
    const info = await sharp(file.path).webp({quality:70}).toFile("some_rule");
        if(info) {
            const deleteFile = await deleteFile(file.filename)            
            console.log(1) 
       }
 }))

}

Answer 2

await在数组迭代功能（forEach，map等）中不起作用

您将必须编写普通循环，

(async()=>{
if (typeof files['images1'] !== 'undefined' && files['images1'].length > 0) {
        await convertToWebp(files['images1'])
        console.log(2)

    }
if (typeof files['images2'] !== 'undefined' && files['images2'].length > 0) {
       await convertToWebp(files['images2'])
        console.log(2)

    }
    console.log(3)

    res.send~
}
})()

async function convertToWebp(files :  MulterFile[]){

for(let i in files){
  const file = files[i]
  await sharp(file.path).webp({quality:70}).toFile("some_rule")
  await deleteFile(file.filename)

}

node.js异步并等待multer问题

2 个答案: