Question

在spring-data-jpa项目中，我有两个实体处于一对多关系。

父实体-

@Entity
@Table(name = "code_group")
public class CodeGroup implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE)
    private Long id;

    @NaturalId
    @Column(nullable = false)
    private String entityId;

    @OneToMany
    @JoinColumn(name = "codeGroupId", referencedColumnName = "entityId")
    private List<SystemCode> systemCodes;

    // .. getters setters
}

子实体-

@Entity
@Table(name = "system_code")
public class SystemCode implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE)
    private Long id;

    @Column(nullable = false)
    private String codeGroupId;

    @Column(nullable = false)
    @Enumerated(EnumType.STRING)
    private ActiveOrInactive status;

    // getters and setters
}

status列为枚举类型，它只能具有Active或Inactive值。

我现有的代码工作正常。它正在获取具有相关系统代码的代码组。我想用status='Active'过滤系统代码。该怎么做？

Answer 1

尝试这样：

@OneToMany
@JoinColumn(name = "codeGroupId", referencedColumnName = "entityId")
@Where(clause = "status= 'Active'")
private List<SystemCode> systemCodes;

Answer 2

您可以在您的仓库中创建此类方法：

List<CodeGroup> getAllBySystemCodes_Status(ActiveOrInactive status);

default List<CodeGroup> getAllActive() {
     return getAllBySystemCodes_Status(ActiveOrInactive.Active);
}

default List<CodeGroup> getAllInactive() {
     return getAllBySystemCodes_Status(ActiveOrInactive.Inactive);
}

JPA一对多，获取具有特定列值的子级

2 个答案: