我的数据库上有通知表,该表使用的值类似于json。
这是我的桌子
id | touserid | data
1 2 a:1:{i:0;s:10:"INV-000001";}
2 2 a:1:{i:0;s:10:"INV-000003";}
3 2 a:1:{i:0;s:15:"The Mej Hotel";}
4 1 a:5:{i:0;s:28:"Total Goalsi:1;s:7:"6250000";}
5 1 a:1:{i:0;s:10:"INV-000007";}
我想在html表中使用该值,但是我不知道如何在codeigniter中将该值转换为html表
这是我的查看代码
<table class="table table-dark">
<tbody>
<thead>
<tr>
<th scope="col">#</th>
<th scope="col">Data</th>
<
</tr>
</thead>
<tbody>
<?php foreach($notifications as $notif){ ?>
<tr>
<td><?php echo $notif['id'] ?></td>
<td><?php echo $notif['data'] ?></td>
</tr>
<?php } ?>
</tbody>
</table>
这是控制器代码
$this->db->limit($this->misc_model->get_notifications_limit(), $offset);
$this->db->where('touserid', get_staff_user_id());
$this->db->order_by('date', 'desc');
$data['notifications'] = $this->db->get(db_prefix() . 'notifications')->result_array();
$this->load->view('admin/sales/sales', $data);
但是我没有看到数据值像我想要的那样进入html表,在表中显示了错误消息“ not_goal_message_failedArray”
我正在尝试对json进行编码,但我仍然不知道如何在控制器中传递json编码以在codeigniter中查看
这是json编码
$page = $this->input->post('page');
$offset = ($page * $this->misc_model->get_notifications_limit());
$this->db->limit($this->misc_model->get_notifications_limit(), $offset);
$this->db->where('touserid', get_staff_user_id());
$this->db->order_by('date', 'desc');
$notifications = $this->db->get(db_prefix() . 'notifications')->result_array();
$i = 0;
foreach ($notifications as $notification) {
if (($notification['fromcompany'] == null && $notification['fromuserid'] != 0) || ($notification['fromcompany'] == null && $notification['fromclientid'] != 0)) {
if ($notification['fromuserid'] != 0) {
$notifications[$i]['profile_image'] = '<a href="' . admin_url('staff/profile/' . $notification['fromuserid']) . '">' . staff_profile_image($notification['fromuserid'], [
'staff-profile-image-small',
'img-circle',
'pull-left',
]) . '</a>';
} else {
$notifications[$i]['profile_image'] = '<a href="' . admin_url('clients/client/' . $notification['fromclientid']) . '">
<img class="client-profile-image-small img-circle pull-left" src="' . contact_profile_image_url($notification['fromclientid']) . '"></a>';
}
} else {
$notifications[$i]['profile_image'] = '';
$notifications[$i]['full_name'] = '';
}
$data = '';
if (!empty($notification['data'])) {
$data = unserialize($notification['data']);
$x = 0;
foreach ($data as $dt) {
if (strpos($dt, '<lang>') !== false) {
$lang = get_string_between($dt, '<lang>', '</lang>');
$temp = _l($lang);
if (strpos($temp, 'project_status_') !== false) {
$status = get_project_status_by_id(strafter($temp, 'project_status_'));
$temp = $status['name'];
}
$dt[$x] = $temp;
}
$x++;
}
}
$notifications[$i]['description'] = _l($notification['description'], $dt);
$notifications[$i]['date'] = time_ago($notification['date']);
$notifications[$i]['full_date'] = $notification['date'];
$i++;
}
echo json_encode($notifications);
尝试将表中的json值转换为html表代码时,您知道我的错误在哪里吗?
谢谢
答案 0 :(得分:0)
您将不会通过echo获取数据,应使用
$ this-> load-> view(“ notification_view”,$ notifications);
代替
echo json_encode($notifications);