Question

源表-类别树

id, parent_id, state, name

我们有

id = 4, parent_id = 0, state = 1, name = SubCategory 0 (root)
id = 8, parent_id = 4, state = 0, name = SubCategory 1
id = 15, parent_id = 8, state = 1, name = SubCategory 2
id = 36, parent_id = 15, state = 1, name = SubCategory 3

作为检查所有父母状态的单个请求，如果至少一个状态= 0，则样本结果应为0行

尝试过递归

WITH RECURSIVE cte (id, state, parent_id, name) AS (
      SELECT     id,
                 state,
                 parent_id,
                 name
      FROM       t_pages
      WHERE      id = 36
      UNION ALL
      SELECT     p.id,
                 p.state,
                 p.parent_id,
                 p.name
      FROM       t_pages p
      INNER JOIN cte
                 ON p.id = cte.parent_id
                 AND p.state = 1
    )
    SELECT * FROM cte;

但是我不认为如何正确设置条件。在以上版本中，总是1选项给出（这是合乎逻辑的）好吧，这太慢了-每张表有200个条目需要0.5秒

还有其他选择吗？

UPD：提琴https://dbfiddle.uk/?rdbms=mariadb_10.4&fiddle=ecdbd0252a87aed8d3c6f5b3a31e0297

如何检查树中所有父母的表中字段的状态

0 个答案: