Question

我正在尝试从json api获取数据，并将返回的数组转换为模型的集合。因此api返回具有id和name字段的用户数组。当我将json转换为模型时，我得到了正确数量的元素，但是模型中的所有属性均为null。

我尝试同时使用水合物和填充模型以将json转换为模型。

        $client = new Client(); //GuzzleHttp\Client
        $request = new \GuzzleHttp\Psr7\Request('GET', 'https://test.com/users');
        $json = $client->sendAsync($request)->then(
            function ($response) {
                return $response->getBody()->getContents();
            }, function ($exception) {
                return $exception->getMessage();
            }
        )->wait();

$object = (array)json_decode($json);
$collection = User::hydrate($object);
return UserResource::collection($collection);

class UserResource extends JsonResource
{
    public static $wrap = null;

    /**
     * Transform the resource into an array.
     *
     * @param  \Illuminate\Http\Request $request
     * @return array
     */
    public function toArray($request)
    {

        return [
            'id' => $this->name,
            'name' => $this->nameCombo,
        ];
    }
}

通话结束后，控制器将返回

{“ data”：[{“ id”：null，“ name”：null}，{“ id”：null，“ name”：null}]}

json返回不为null的ID和名称

Answer 1

我正在测试此代码，并且工作正常：

        $client = new Client(); //GuzzleHttp\Client
        $request = new \GuzzleHttp\Psr7\Request('GET', 'https://jsonplaceholder.typicode.com/users');
        $json = $client->sendAsync($request)->then(
            function ($response) {
                return $response->getBody()->getContents();
            }, function ($exception) {
            return $exception->getMessage();
        }
        )->wait();

        $object = (array)json_decode($json);
        $collection = User::hydrate($object);

        return UserResource::collection($collection);

class UserResource extends JsonResource
{
    public static $wrap = null;

    /**
     * Transform the resource into an array.
     *
     * @return array
     */
    public function toArray()
    {
        return [
            'id' => $this->id,
            'name' => $this->name,
        ];
    }
}

您确定这部分正确吗？

        return [
            'id' => $this->name,
            'name' => $this->nameCombo,
        ];

转换枪口响应t Laravel模型

1 个答案: