library(ZillowR)
library(tidyverse)
#Try
# Sample data
set_zillow_web_service_id("X1-ZWz17seirkzuh7_93aho")
map2_dfr(sample3$Street, sample3$ZipCode,
~{GetDeepSearchResults(address = .x,
citystatezip = as.character(.y),
rentzestimate=FALSE) %>%
unlist() %>%
enframe()
}) %>%
filter(!str_detect(value, "text"))
使用数据面食对数据进行采样:
tibble::tribble(
~AccountId, ~ZipCode, ~Totalestimate, ~ZipHhIncome, ~Street, ~State, ~xxxxxxxxxxxxPct, ~ZipPctAdvDegree, ~AgeFactorPct, ~City,
464641, 43130, 0, 46205, "2577 Long Bow Ave", "OH", 0.8, 0.058499952, 0.7, "Lancaster",
451304, 44718, 0, 69396, "4822 Armandale Nw", "OH", 0.8, 0.171958907, 0.7, "Canton",
443925, 8837, 0, 74764, "348 Grandview Ave", "NJ", 1, 0.16989858, 0.7, "Edison",
464725, 2032, 147, 100658, "81 Rhoades Ave", "MA", 1.3, 0.247449819, 0.7, "East Walpole",
431671, 89403, 335.86, 55248, "296 Monte Cristo Dr.", "NV", 0.8, 0.066260613, 0.7, "Dayton",
474844, 99703, 61.05, 53031, "4348 9th Street", "AK", 1.05, 0.061620898, 0.8, "Fort Wainwright",
440990, 55429, 0, 43835, "5649 Vera Cruz Ave N", "MN", 1, 0.050472833, 0.7, "Crystal"
)
如何获取getdeepsearchresults api的输出?我希望我的查询命中api并返回参数的每一行的结果,即地址(街道)和邮政编码(citystatezip)
答案 0 :(得分:0)
获取address
和citystatezip
的一种方法是使用map2_df
/ map2_dfr
并将Street
和ZipCode
传递给{{1 },然后仅提取感兴趣的属性。
GetDeepSearchResults
或使用基数R library(ZillowR)
purrr::map2_df(sample$Street, as.character(sample$ZipCode), ~{
temp <- GetDeepSearchResults(address = .x,citystatezip = .y)
tibble(Address = temp$request$address, Zip = temp$request$citystatezip)
})
# A tibble: 7 x 2
# Address Zip
# <chr> <chr>
#1 2577 Long Bow Ave 43130
#2 4822 Armandale Nw 44718
#3 348 Grandview Ave 8837
#4 81 Rhoades Ave 2032
#5 296 Monte Cristo Dr. 89403
#6 4348 9th Street 99703
#7 5649 Vera Cruz Ave N 55429
Map