Question

通过运行：

$users = User::with('cars')->when(isset($data['cars']), function($query) use ($data) {
    $query->withCount(['cars' => function($query2) use ($data) {
        $query2->having('cars_count', $data['cars']);
    }]);
})->paginate(10);

Laravel做什么：

select `users`.*, (select count(*) from `cars` where `users`.`id` = `cars`.`user_id` having `cars_count` = 32) as `cars_count` from `users` limit 10 offset 100

我收到此错误：

SQLSTATE[42S22]: Column not found: 1247 Reference 'cars_count' not supported (forward reference in item list)

我想要它做什么：

select `users`.*, (select count(*) from `cars` where `users`.`id` = `cars`.`user_id`) as `cars_count` from `users` having `cars_count` = 32 limit 10 offset 100

Answer 1

以下内容使我可以匹配您所需的查询。我在构建器实例上使用->toSql()在下面显示它。

$users = User::with('cars')->when(isset($data['cars']), function($query) use ($data) {
    $query
        ->withCount('cars')
        ->having('cars_count', $data['cars']);
})->paginate(10);

输出（我的页面没有分页）

mine:  select `users`.*, (select count(*) from `cars` where `users`.`id` = `cars`.`user_id`) as `cars_count` from `users` having `cars_count` = ?
yours: select `users`.*, (select count(*) from `cars` where `users`.`id` = `cars`.`user_id`) as `cars_count` from `users` having `cars_count` = 32 limit 10 offset 100

编辑

我正在添加一个链接，该链接应该允许使用having分页，因为默认情况下在Laravel中这是不可能的。
https://github.com/justbetter/laravel-pagination-with-havings

Laravel-withCount返回错误，提示SQLSTATE [42S22]：找不到列：1247不支持引用“ cars_count”（项目列表中的转发引用）

1 个答案: