python3在Ubuntu上命名为子进程

Question

我正在运行与此类似的代码：

def listen():
    with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
        s.bind((HOST, PORT))
        s.listen()
        conn, addr = s.accept()
        with conn:
            print('Connected by', addr)
            while True:
                data = conn.recv(1024)
                if not data:
                    break
                #conn.sendall(data)
                print(data)

def main():
    newpid = os.fork()
    if newpid == 0:
        listen()
    else:
        pids = (os.getpid(), newpid)
        print("parent: %d, child: %d\n" % pids)

    sys.exit()

if __name__=="__main__":
    main()

当我将其作为服务运行，因此系统状态为..时，我会看到类似这样的内容：

● .service - listen for url input.
   Loaded: loaded (/lib/systemd/system/.service; enabled; vendor preset: enabled)
   Active: active (running) since Mon 2019-07-15 18:50:35 EDT; 1s ago
 Main PID: 11618 (python)
    Tasks: 2 (limit: 4915)
   CGroup: /system.slice/.service
           ├─11618 //venv/bin/python /.py
           └─11619 //venv/bin/python /.py

很明显，哪个进程是父进程，哪个进程是子进程，但是我需要从子进程等生成子进程，并需要命名它们/从systemctl显示更好的树。这可能吗？