正则表达式测试'*'是否出现在字符串的末尾

Question

嗨，我对正则表达式不太满意，在这里有点挣扎。我想测试一个字符串，看看它里面是否有'*'，它只有一个，并且是字符串中的最后一个字符。

例如

'jflkasjkdfjkslf'  // matches because it has no *
'*'                // matches because it has a * and it is last character
'sdkfjksajdflkj*'  // matches because it has a * and it is last character

'jasldk*aksjdf'  // doesn't match because it has a * and it is not in last position
'asdjflkasjfd**' // doesn't match because it has more than one *
'asdjf*lkasjfd*' // doesn't match because it has more than one *

到目前为止，我(\*)$只是测试它是否以*结尾，所以我还差得远...：（。

谢谢！

Answer 1

您可以使用

^[^*]*\*?$

请参见regex demo和regex graph：

详细信息

• ^-字符串的开头
• [^*]*-除*之外的0个或更多字符
• \*?-可选的*
• $-字符串结尾