Question

我正在尝试获取ID的修改日期早于7天的最新记录，但是，结果将返回ID早于7天的记录的所有记录。

SELECT USERID
FROM [PROJ]
INNER JOIN [NOTES] ON [PROJ].id = [NOTES].projID
WHERE [PROJ.STATUS] = 'ACTIVE'
  AND [NOTES.MODIFIEDDATE] <= GETDATE() - 7

返回：

project              userId        modifieddate
 1. 20190101              6           07/02/2019 *
 2. 20190101              6           07/01/2019
 3. 20190101              6           06/29/2019
 4. 20190102              7           07/04/2019 *
 5. 20190102              7           07/03/2019

*是我期望返回的结果。这将返回所有ID注释的修改日期小于7天的所有记录，我只希望最近的注释（修改日期）早于7天。

Answer 1

尝试添加一个hading子句

SELECT USERID
FROM [PROJ]
INNER JOIN [NOTES] ON [PROJ].id = [NOTES].projID
WHERE [PROJ.STATUS] = 'ACTIVE'
  AND [NOTES.MODIFIEDDATE] <= GETDATE() - 7 
GROUP BY USERID
HAVING MAX([NOTES.MODIFIEDDATE])

编辑：如果您只想要最新的，那我将完全摆脱

AND [NOTES.MODIFIEDDATE] <= GETDATE() - 7 

SELECT USERID
    FROM [PROJ]
    INNER JOIN [NOTES] ON [PROJ].id = [NOTES].projID
    WHERE [PROJ.STATUS] = 'ACTIVE'
    GROUP BY USERID
    HAVING MAX([NOTES.MODIFIEDDATE])

EDIT2：

SELECT USERID
    FROM [PROJ]
    INNER JOIN [NOTES] ON [PROJ].id = [NOTES].projID
    WHERE [PROJ.STATUS] = 'ACTIVE'
      AND [NOTES.MODIFIEDDATE] <= GETDATE() - 7 
    GROUP BY USERID, PROJECT
    HAVING MAX([NOTES.MODIFIEDDATE])

使每条记录的最新修改日期早于7天且有多个日期

1 个答案: