幻灯片和ajax的问题

时间:2011-04-18 14:29:39

标签: javascript jquery ajax

我的html中有这个结构

 <div id ="slide1">
            <form method="post" id="customForm" action="">
                //my content - name, email, mypassword, pass2
            </form> //i already tried delete this
        </div>
        <div id ="slide2">
            <form method="post" id="customForm1" action="">  //and this, to have only one form obviously this didn't work, because the div of slide1 is already closed.
                //my content - other stuff
            </form>
        </div>

我有这个JS

 $(document).ready(function() {
        $("#customForm").submit(function() {
            $.ajax({
                url: "validation1.php",
                type: "post",
                dataType: "json",
                data: {
                    name: $('#name').val(),
                    email: $('#email').val(),
                    myPassword: $('#myPassword').val(),
                    pass2: $('#pass2').val()
                },
                success: function(data) {
//stuff
}
问题是。我想将幻灯片的数据分组并发送到validation1.php,但为此我必须有一个唯一的表单。

如果问题不明确,请告诉我。

感谢

1 个答案:

答案 0 :(得分:0)

如果我理解正确你说你需要在一个帖子中发送2张幻灯片,但在你的html中,数据存在于2个表单元素中。

您始终可以使用所需的数据构建新表单并提交,然后还要检查页面上表单的使用情况。

var href = '.... where ever you are sending the data .....';
var form = $('<form method="post" action="' + href + '"></form>');

var d1=$('.slide1 some subdata selector');
var d2=$('.slide2 some subdata selector')

$('<input type="hidden" name="data1">').val(d1).appendTo(form);
$('<input type="hidden" name="data2">').val(d2).appendTo(form);
$('body').append(form);
form.submit();
form.detach();