Question

我正在尝试使用cheerio js从此页面获取数据：

var html =
"<div class='clear'>" +
"<div class='time_head'>time_head content1</div>"
+ "<div class='blockfix'>blockfix1</div>"
+ "<div class='blockfix'>blockfix2</div>"
+ "<div class='time_head'>time_head content2</div>"
+ "<div class='blockfix'>blockfix3</div>"
+ "<div class='blockfix'>blockfix4</div>"
+ "<div class='blockfix'>blockfix5</div>"
+ "</div>";

这是我到目前为止尝试过的：

$ = cheerio.load(html);
let devtoList = [];

$('.clear').each(function (i, elem) {
  devtoList[i] = {
    title: $(this).find('.time_head').text(),
    game: $(this).find('.blockfix').text()
  };
});
const devtoListTrimmed = devtoList.filter(n => n != undefined);
console.log(devtoListTrimmed);

结果是：

[ 
  { title: 'time_head content1time_head content2',
    game: 'blockfix1blockfix2blockfix3blockfix4blockfix5' } 
]

但是我需要每个time_head及其blockfix

TIME_HEAD CONTENT1
   ----blockfix1
   ----blockfix2
TIME_HEAD CONTENT2
   ----blockfix3
   ----blockfix4

请注意： 1- time_head的数量总是变化 2-我愿意接受其他解决方案

Answer 1

使用.time_head获取所有元素，对其进行迭代，应用while循环，直到下一个元素具有类blockfix。

const output = [];
$('.time_head').each(function(i) {
  let next = $(this).next('.blockfix');
  output.push({"title": $(this).text(), game: []});
  while(next) {
    output[i].game.push(next.text());
    const isNext = $(next).next('.blockfix');
    next = isNext.length > 0 ? $(next).next('.blockfix') : false;
  }
});

console.log(output);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class='clear'>
            <div class='time_head'>time_head content1</div>
            <div class='blockfix'>blockfix1</div>
            <div class='blockfix'>blockfix2</div>
            <div class='time_head'>time_head content2</div>
            <div class='blockfix'>blockfix3</div>
            <div class='blockfix'>blockfix4</div>
            <div class='blockfix'>blockfix5</div>
        </div>

抓取HTML页面结果..顺序不正确

1 个答案: