在这个(示例)xml中,我需要给诸如<book1>
,<book2>
等的书签编号。
结果XML将被导入,因此需要该符号。结果将永远不会有超过6个书节点。我写的xslt全部命名为<book>
这是原始xml
<?xml version="1.0"?>
<catalog>
<book>
<author>Gambardella, Matthew</author>
<title>XML Developer's Guide</title>
</book>
<book>
<author>Ralls, Kim</author>
<title>Midnight Rain</title>
</book>
<book>
<author>Corets, Eva</author>
<title>Maeve Ascendant</title>
</book>
<book>
<author>Randall, Cynthia</author>
<title>Lover Birds</title>
</book>
<book>
<author>Corets, Eva</author>
<title>Oberon's Legacy</title>
</book>
<book>
<author>Corets, Eva</author>
<title>The Sundered Grail</title>
</book>
<book>
<author>Thurman, Paula</author>
<title>Splish Splash</title>
</book>
</catalog>
这是我已经拥有的xsl:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="catalog">
<catalog>
<xsl:if test="//book[author='Corets, Eva']">
<book>
<sample>Here comes info about Eva Corets</sample>
</book>
</xsl:if>
<xsl:if test="//book[author='Ralls, Kim']">
<book>
<sample>Here comes info about Kim Ralls</sample>
</book>
</xsl:if>
<xsl:if test="//book[author='Thurman, Paula']">
<book>
<sample>Here comes info about Paula Thurman</sample>
</book>
</xsl:if>
</catalog>
</xsl:template>
</xsl:stylesheet>
哪个输出:
<?xml version="1.0" encoding="UTF-8"?>
<catalog>
<book>
<sample>Here comes info about Eva Corets</sample>
</book>
<book>
<sample>Here comes info about Kim Ralls</sample>
</book>
<book>
<sample>Here comes info about Paula Thurman</sample>
</book>
</catalog>
这是我需要的:
<?xml version="1.0" encoding="UTF-8"?>
<catalog>
<book1>
<sample>Here comes info about Eva Corets</sample>
</book1>
<book2>
<sample>Here comes info about Kim Ralls</sample>
</book2>
<book3>
<sample>Here comes info about Paula Thurman</sample>
</book3>
</catalog>
答案 0 :(得分:0)
这应该做。
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="catalog">
<catalog>
<xsl:for-each select="book[author='Corets, Eva']">
<xsl:variable name="book_el" select="concat('book', position())"></xsl:variable>
<xsl:element name="{$book_el}">
<xsl:copy-of select="node()"/>
</xsl:element>
</xsl:for-each>
</catalog>
</xsl:template>
</xsl:stylesheet>
答案 1 :(得分:0)
如果您只能使用XSLT 1.0,则可以使用技术调用Muenchian Grouping从书中找寻不同的作者,尽管您需要额外的工作才能按特定的顺序找他们。
尝试使用此XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:key name="books" match="book" use="author" />
<xsl:param name="authors">|Corets, Eva|Ralls, Kim|Thurman, Paula|</xsl:param>
<xsl:template match="catalog">
<catalog>
<xsl:for-each select="book[contains($authors, concat('|', author, '|'))][generate-id() = generate-id(key('books', author)[1])]">
<xsl:sort select="string-length(substring-before($authors, concat('|', author, '|')))" />
<xsl:element name="book{position()}">
<sample>
<xsl:text>Here comes info about </xsl:text>
<xsl:value-of select="author" />
</sample>
<info>
<xsl:for-each select="key('books', author)">
<xsl:if test="position() > 1">, </xsl:if>
<xsl:value-of select="title" />
</xsl:for-each>
</info>
</xsl:element>
</xsl:for-each>
</catalog>
</xsl:template>
</xsl:stylesheet>
如果您只想按字母顺序列出xsl:sort
,则可以将<xsl:sort select="author" />
替换为For i= 8 To Split(sheetXls.UsedRange.Address, "$")(4)
。