Question

在您看来，除了我指定的日期范围外，我该如何帮助您解决问题？

未列出7月1日至7月12日之间的时间

https://i.hizliresim.com/od7YzX.jpg

SELECT DISTINCT 
                         s.A, CONVERT(varchar, d.timein, 104) AS G
FROM            DATABASE.table1 AS a INNER JOIN
                         DATABASE.table2 AS b ON a.x = b.y INNER JOIN
                         DATABASE.dbo.table3 AS c ON b.b = c.d INNER JOIN
                         DATABASE.dbo.table4 AS e ON c.f = e.r INNER JOIN
                         DATABASE.table5 AS d ON e.t = d.u INNER JOIN
                         DATABASE.table6 AS s ON a.fr = s.rf INNER JOIN
                         DATABASE.table7 AS si ON d.er = si.pr INNER JOIN
                         DATABASE.table8 AS i ON si.dd = i.gt INNER JOIN
                         DATABASE.table9 AS ck ON s.mkk = ck.pxx
WHERE         (CONVERT(varchar, d.timein, 104) BETWEEN '01.07.2019' AND '12.07.2019')

Answer 1

尝试使用日期格式为'yyyy-MM-dd'

BETWEEN '2019-07-01' AND '2019-07-12'

Answer 2

不比较字符串日期，不比较日期。

WHERE d.timein BETWEEN '2019-07-01' AND '2019-07-12'

请注意，这将返回介于2019-07-01 00:00:00和2019-07-12 00:00:00之间的日期，因此您可能需要使用2019-07-13或2019-07-12 23:59:59

比较字符串时，它会从左到右比较字符，因此，10.12.2018在01.07.2019和12.07.2019之间，因为10在{{ 1}}和01

列出了错误的日期范围

2 个答案: