Question

我可以保存项目，但不能查询。

items=PhoneItem.objects.all()
    for item in items:
        print(item)

程序抛出错误：

在“用于项中的项：”中引发异常： init （）接受4个位置参数，但给出了11个

我尝试重新启动程序，但问题仍然存在。

class PhoneItem(models.Model):

     name = models.CharField(max_length=1000)
     phoneNumber = models.CharField(max_length=1000)
     department = models.CharField(max_length=1000)
     namePY = models.CharField(max_length=1000)
     phoneNumberPY = models.CharField(max_length=1000)
     departmentPY = models.CharField(max_length=1000)
     namePinyin = models.CharField(max_length=1000)
     phoneNumberPinyin = models.CharField(max_length=1000)
     departmentPinyin = models.CharField(max_length=1000)
     pass

    def toPY(self,text):
        pinyin=lazy_pinyin(text)
        res=''
        for py in pinyin:
            res=res+py[0]
            pass
        return res

    def toPinyin(self,text):
        pinyin = lazy_pinyin(text)
        res = ''
        for py in pinyin:
            res = res + py
            pass
        return res

    def __init__(self,name,phoneNumber,department):
        super(PhoneItem, self).__init__()
        self.name=name
        self.phoneNumber=phoneNumber
        self.department=department
        self.namePY=self.toPY(name)
        self.phoneNumberPY = self.toPY(phoneNumber)
        self.departmentPY = self.toPY(department)
        self.namePinyin = self.toPinyin(name)
        self.phoneNumberPinyin = self.toPinyin(phoneNumber)
        self.departmentPinyin = self.toPinyin(department)
        pass
    pass

我希望输出所有项目结果。

Answer 1

您已经重写了init。但是Django需要在init中获取所有字段，而别无其他：9您的字段，id和self。如果要重写init，则需要编写所有参数。最简单的方法是像这样重写init create factory方法：

class PhoneItem(models.Model):

    @classmethod
    def new(cls,name, phoneNumber, department):
        return ...

或者您可以这样做：

class PhoneItem(models.Model):

   def __init__(self, name, phoneNumber, department, **kwargs):
       super().__init__(name=name, department=department, **kwargs)
       # And everything you need is here

如何输出查询结果？

1 个答案: