我想从几个表中选择*,但要消除重复项而又不写出所有列名。组合表中大约有30列,我不想将每一列都写出来。
我知道我可以写出所有列名,但是我想看看是否有一种方法可以使用select *
SELECT
a.*
FROM "T1"."T2"."T3" a
LEFT JOIN "T1"."T2"."T4" b on b.id = a.id
LEFT JOIN "T1"."T2"."T5" c on c.id = a.id
LEFT JOIN "T1"."T2"."T6" d on d.id = a.id
WHERE a.org = '123' AND kind = 'abc'
有没有一种方法可以通过a.id进行分组而不必写出每个列的名称?最终表中的原始列为41列,我试图仅返回id上的不同行。
答案 0 :(得分:0)
不是完全group by
,而是row_number()
:
SELECT a.*
FROM (SELECT a.*,
ROW_NUMBER() OVER (PARTITION BY a.id ORDER BY a.id) as seqnum
FROM "T1"."T2"."T3" a LEFT JOIN
"T1"."T2"."T4" b
ON b.id = a.id LEFT JOIN
"T1"."T2"."T5" c
ON c.id = a.id LEFT JOIN
"T1"."T2"."T6" d
ON d.id = a.id
WHERE a.org = '123' AND kind = 'abc'
) a
WHERE seqnum = 1;