SSMS脚本选项

Question

使用 SSMS 18.0 Preview 6 编写函数脚本会产生以下脚本。

  @ViewChild('formRecipe') formRecipe: ngForm; 

  //or, if using angular8,
  // @ViewChild('formRecipe',{static : true}) formRecipe: ngForm; 

 constructor(private changeDetectorRef: ChangeDetectorRef){}

 onCloseMember(){
    this.formRecipe.reset();
   this.changeDetectorRef.detectChanges();
 }

使用 SSMS 2016 编写相同功能的脚本会产生该脚本

/****** Object:  UserDefinedFunction [dbo].[sfn_Proper_Case]    Script Date: 7/13/2019 9:57:36 AM ******/
SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER ON
GO

IF NOT EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[sfn_Proper_Case]') AND type in (N'FN', N'IF', N'TF', N'FS', N'FT'))
BEGIN
execute dbo.sp_executesql @statement = N'
CREATE FUNCTION [dbo].[sfn_Proper_Case]
                (
                @input    NVARCHAR(4000)
                )
RETURNS NVARCHAR(4000)
AS
    BEGIN

        SET @input = REPLACE(REPLACE(REPLACE(@input,'' '',''<>''),''><'',''''),''<>'','' '');

        DECLARE @output    NVARCHAR(512);
        DECLARE @current_position    INT = 1;

        IF DATALENGTH(@input) > 0
        BEGIN
            SET @output = '''';
        END;

        WHILE @current_position <= DATALENGTH(@input)
        BEGIN
            DECLARE @check_character     NVARCHAR(1);
            DECLARE @previous_character  NVARCHAR(1);
            DECLARE @output_character    NVARCHAR(1);

            SELECT @check_character = LOWER(SUBSTRING(@input,@current_position,1));
            SELECT @previous_character = SUBSTRING(@input,@current_position
                                                          - 1,1);

            IF @previous_character NOT LIKE ''[a-z]''
               AND @check_character LIKE ''[a-z]''
            BEGIN
                SELECT @output_character = UPPER(@check_character);
            END;
                ELSE
            BEGIN
                SELECT @output_character = @check_character;
            END;

            SET @output = @output
                          + @output_character;
            SET @current_position = @current_position
                                    + 1;
        END;

        RETURN @output;

    END;

' 
END
GO

问题-我需要在SSMS 18中更改哪些脚本选项，因此它不会在使用 {生成的输出脚本中添加/****** Object: UserDefinedFunction [dbo].[sfn_Proper_Case] Script Date: 7/13/2019 9:55:43 AM ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE FUNCTION [dbo].[sfn_Proper_Case] ( @input NVARCHAR(4000) ) RETURNS NVARCHAR(4000) AS BEGIN SET @input = REPLACE(REPLACE(REPLACE(@input,' ','<>'),'><',''),'<>',' '); DECLARE @output NVARCHAR(512); DECLARE @current_position INT = 1; IF DATALENGTH(@input) > 0 BEGIN SET @output = ''; END; WHILE @current_position <= DATALENGTH(@input) BEGIN DECLARE @check_character NVARCHAR(1); DECLARE @previous_character NVARCHAR(1); DECLARE @output_character NVARCHAR(1); SELECT @check_character = LOWER(SUBSTRING(@input,@current_position,1)); SELECT @previous_character = SUBSTRING(@input,@current_position - 1,1); IF @previous_character NOT LIKE '[a-z]' AND @check_character LIKE '[a-z]' BEGIN SELECT @output_character = UPPER(@check_character); END; ELSE BEGIN SELECT @output_character = @check_character; END; SET @output = @output + @output_character; SET @current_position = @current_position + 1; END; RETURN @output; END; GO 前缀和双引号N' {1}} 或 ''string literals''

此选项有效，但我不想删除对象 Right Click->Script Function as->CREATE TO

PS：我不记得是否在SSMS 2016的脚本选项下进行了更改以实现此目的，或者它是否是默认设置。谢谢！

Answer 1

您可以在以下位置更改此行为：

  

SSMS->工具->选项-> SQL Server对象资源管理器->脚本->对象   脚本选项

对于SSMS 16，属性Include IF NOT EXISTS clause应设置为False

^{图片来源：https://social.microsoft.com/Forums/getfile/14300/}

对于SSMS 18，属性Check for object existence应该设置为False