将ByteBuffer bbuf_src
中尽可能多的字节放入另一个ByteBuffer bbuf_dest
(以及知道传输了多少字节)的最有效方法是什么?我正在尝试bbuf_dest.put(bbuf_src)
但似乎想要抛出一个BufferOverflowException,当我需要它时,我现在无法从Sun获得javadoc(网络问题)。 > :( argh。
编辑:darnit,@ Richard的方法(在bbuf_src
的支持数组中使用put())如果bbuf_src是ReadOnly缓冲区将无效,因为您无法访问该数组。在那种情况下我该怎么办?
答案 0 :(得分:9)
正如您所发现的那样,获取后备阵列并不总是有效(对于只读缓冲区,直接缓冲区和内存映射文件缓冲区而言,它会失败)。更好的选择是复制源缓冲区并为要传输的数据量设置新的限制:
int maxTransfer = Math.min(bbuf_dest.remaining(), bbuf_src.remaining());
// use a duplicated buffer so we don't disrupt the limit of the original buffer
ByteBuffer bbuf_tmp = bbuf_src.duplicate ();
bbuf_tmp.limit (bbuf_tmp.position() + maxTransfer);
bbuf_dest.put (bbuf_tmp);
// now discard the data we've copied from the original source (optional)
bbuf_src.position(bbuf_src.position() + maxTransfer);
答案 1 :(得分:3)
好的,我已经改编了@ Richard的回答:
public static int transferAsMuchAsPossible(
ByteBuffer bbuf_dest, ByteBuffer bbuf_src)
{
int nTransfer = Math.min(bbuf_dest.remaining(), bbuf_src.remaining());
if (nTransfer > 0)
{
bbuf_dest.put(bbuf_src.array(),
bbuf_src.arrayOffset()+bbuf_src.position(),
nTransfer);
bbuf_src.position(bbuf_src.position()+nTransfer);
}
return nTransfer;
}
并进行测试以确保其有效:
public static boolean transferTest()
{
ByteBuffer bb1 = ByteBuffer.allocate(256);
ByteBuffer bb2 = ByteBuffer.allocate(50);
for (int i = 0; i < 100; ++i)
{
bb1.put((byte)i);
}
bb1.flip();
bb1.position(5);
ByteBuffer bb1a = bb1.slice();
bb1a.position(2);
// bb3 includes the 5-100 range
bb2.put((byte)77);
// something to see this works when bb2 isn't empty
int n = transferAsMuchAsPossible(bb2, bb1a);
boolean itWorked = (n == 49);
if (bb1a.position() != 51)
itWorked = false;
if (bb2.position() != 50)
itWorked = false;
bb2.rewind();
if (bb2.get() != 77)
itWorked = false;
for (int i = 0; i < 49; ++i)
{
if (bb2.get() != i+7)
{
itWorked = false;
break;
}
}
return itWorked;
}
答案 2 :(得分:1)
你得到BufferOverflowException,因为你的bbuf_dest不够大。
您需要使用bbuf_dest.remaining()来查找可以从bbuf_src传输的最大字节数:
int maxTransfer = Math.min(bbuf_dest.remaining(), bbuf_src.remaining());
bbuf_dest.put(bbuf_src.array(), 0, maxTransfer);