Question

我想编写一种排序逻辑，以将以下字符串排序为自定义类的输出：-

现在输出：- 3m_20,2m_20,1m_20,10d_20,5d_20,0d_20,0d_0,5d_0,10d_0,1m_0,2m_0,3m_0

必需的输出 0d_0,0d_20,5d_0,5d_20,10d_0,10d_20,1m_0,1m_20,2m_0,2m_20,3m_0,3m_20

我发现很难以上述方式进行复杂的排序。请帮我如何按要求排序？

我曾尝试根据IId与IComparable进行排序，但根据第一个字符对其进行排序。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;

namespace Rextester
{
    public class Program
    {
        public static void Main(string[] args)
        {
            DateDefinition d1 = new DateDefinition { Horizon = "0d",Days=20};
            DateDefinition d1_0 = new DateDefinition { Horizon = "0d",Days=0};
            DateDefinition d2 = new DateDefinition { Horizon = "5d",Days=20};
            DateDefinition d2_0 = new DateDefinition { Horizon = "5d",Days=0};
            DateDefinition d3 = new DateDefinition { Horizon = "10d",Days=20};
            DateDefinition d3_0 = new DateDefinition { Horizon = "10d",Days=0};
            DateDefinition d4 = new DateDefinition { Horizon = "1m",Days=20};
            DateDefinition d4_0 = new DateDefinition { Horizon = "1m",Days=0};
            DateDefinition d5 = new DateDefinition { Horizon = "2m",Days=20};
            DateDefinition d5_0 = new DateDefinition { Horizon = "2m",Days=0};
            DateDefinition d6 = new DateDefinition { Horizon = "3m",Days=20};
            DateDefinition d6_0 = new DateDefinition { Horizon = "3m",Days=0};

            var definitions = new List<DateDefinition> {d6,d5,d4,d3,d2,d1,d1_0,d2_0,d3_0,d4_0,d5_0,d6_0};

            definitions.Sort();

            foreach(var d in definitions)
            {
                Console.WriteLine(d.Id);
            } 
        }
    }

    public class DateDefinition : IComparable<DateDefinition>
    {
        public string Horizon { get; set; }
        public int Days { get; set; }
        public string Id
        {
            get { return Horizon + "_" + Days.ToString(); }
        }

        public int CompareTo(DateDefinition other)
        {
            if (ReferenceEquals(other, this)) return 0;
            if(ReferenceEquals(other,null)) return -1;
            return string.Compare(Id,other.Id, StringComparison.InvariantCultureIgnoreCase);
        }
    }    
}

输出到上面的代码：-

0d_0 0d_20 10d_0 10d_20 1m_0 1m_20 2m_0 2m_20 3m_0 3m_20 5d_0 5d_20

需要像这样的输出：-

0d_0 0d_20 5d_0 5d_20 10d_0 10d_20 1m_0 1m_20 2m_0 2m_20 3m_0 3m_20

重要提示：在上述情况下，请注意d = days，m = months

Answer 1

在CompareTo方法中，您正在使用string.Compare，因此它将按字母顺序比较两个实例的计算得出的ID属性。按字母顺序，“ 10d_0”在“ 5d_0”之前。

您想要进行某种数值比较，但是您将需要一些东西来将以月表示的Horizon值转换为以天表示的值（反之亦然）以进行有效的比较。

将Horizon属性定义为字符串似乎有点尴尬，因为它似乎包含数字和单位（d代表几天，m代表几个月）。您将需要解析它们并将其转换为数字，或者将Horizon重新定义为数字HorizonValue和字符串HorizonUnits。

如何使用自定义日期字符串创建排序逻辑

1 个答案: