Question

我正在制作井字游戏，我需要用户输入1到9之间的任意位置，然后输入X或O。我需要包括的一些条件是我想限制用户输入更大的数字小于9，并且请勿输入'X'或'O'以外的任何字符。我遇到的问题是它没有遵循条件语句。任何帮助将不胜感激。

void CreateBoard(int m, int n, char board[][n])
{
    int i, j, position;
    char one;
    char two; 
    char temp;
    char xORo;
    int count = 0;
    int end;

    do {
        printf("Enter the number of the cell you want to insert X or O or enter -1 to exit: \n");
        scanf("%d", &position);

        printf("Type X or O: \n");
        scanf(" %c", &xORo);

        if(position < 0){
            break;
        }
        if((position > 9) && xORo != ('X') && ('O'))
        {
            continue;
        }   
        else if((position > 0 || position < 9) && xORo == ('X') && ('O'))
        {
            switch(position)
            {
                case 1: temp = xORo;
                        xORo = board[0][0];
                        board[0][0] = temp; 
                        break;
                case 2: temp = xORo;
                        xORo = board[0][1];
                        board[0][1] = temp; 
                        break;
                case 3: temp = xORo;
                        xORo = board[0][2];
                        board[0][2] = temp; 
                        break;
                case 4: temp = xORo;
                        xORo = board[1][0];
                        board[1][0] = temp; 
                        break;
                case 5: temp = xORo;
                        xORo = board[1][1];
                        board[1][1] = temp; 
                        break;
                case 6: temp = xORo;
                        xORo = board[1][2];
                        board[1][2] = temp; 
                        break;
                case 7: temp = xORo;
                        xORo = board[2][0];
                        board[2][0] = temp; 
                        break;
                case 8: temp = xORo;
                        xORo = board[2][1];
                        board[2][1] = temp; 
                        break;
                case 9: temp = xORo;
                        xORo = board[2][2];
                        board[2][2] = temp; 
                        break;
            }
            PrintBoard(3, 3, board);
        }

    }while(position != -1);
}

Answer 1

您可以通过一点数学来简化。给定索引i，您可以使用以下命令获取行/列：

row = i % 3;
col = i / 3;

请注意，i是0-8，而不是1-9。

您可以使用辅助函数将索引转换为行/列：

void get_row_col(int index, int num_cols, int *row, int *col)
{
    *row = index % num_cols;
    *col = index / num_cols;
}

然后您的功能可以简化为：

void CreateBoard(int m, int n, char board[][n])
{
    int position, row, col;
    char xORo;

    while (1) {
        printf("Enter the number of the cell you want to insert X or O or enter -1 to exit: \n");
        scanf("%d", &position);
        // TODO: Always check the return value from scanf

        if (position == -1) break;

        printf("Type X or O: \n");
        scanf(" %c", &xORo);

        if (position < 1 || position > 9 || (xORo != 'X' && xORo != 'Y')) {
            continue;
        }

        get_row_col(position - 1, 3, &row, &col);
        board[row][col] = xORo;
        PrintBoard(3, 3, board);
    }
}

Answer 2

if((position > 9) && (xORo !='X') && (xORo !='O'))
        {
            continue;
        }

这应该是第二个条件。

else if((position > 0)&&(position < 9)&&(xORo =='X') && (xORo=='O'))

这应该是达到您期望的动机的最终条件。此外，无需在条件（position！=-1）时使用do-while循环，因为在第一个条件中已经实现了这一点。可以使用代码

while(1) {
        printf("Enter the number of the cell you want to insert X or O or enter -1 to exit: \n");
        scanf("%d", &position);

        printf("Type X or O: \n");
        scanf(" %c", &xORo);

        if(position < 0){
            break;
        }
        if((position > 9) && (xORo !='X') && (xORo !='O'))
        {
            continue;
        }   
        else if((position > 0)&&(position < 9)&&(xORo =='X') && (xORo=='O'))
        {
            switch(position)
            {
                case 1: temp = xORo;
                        xORo = board[0][0];
                        board[0][0] = temp; 
                        break;
                case 2: temp = xORo;
                        xORo = board[0][1];
                        board[0][1] = temp; 
                        break;
                case 3: temp = xORo;
                        xORo = board[0][2];
                        board[0][2] = temp; 
                        break;
                case 4: temp = xORo;
                        xORo = board[1][0];
                        board[1][0] = temp; 
                        break;
                case 5: temp = xORo;
                        xORo = board[1][1];
                        board[1][1] = temp; 
                        break;
                case 6: temp = xORo;
                        xORo = board[1][2];
                        board[1][2] = temp; 
                        break;
                case 7: temp = xORo;
                        xORo = board[2][0];
                        board[2][0] = temp; 
                        break;
                case 8: temp = xORo;
                        xORo = board[2][1];
                        board[2][1] = temp; 
                        break;
                case 9: temp = xORo;
                        xORo = board[2][2];
                        board[2][2] = temp; 
                        break;
            }
            PrintBoard(3, 3, board);
        }

    }
}

如何使用&&和||编写具有多个条件的if语句？

2 个答案: