如何通过uilongPressGestureRecognizer获取button.tag?

时间:2011-04-18 09:36:59

标签: iphone cocoa-touch button tags sender

我正在动态地将图像按钮添加到某些滚动视图中。他们都指向一个longPressHandler。现在,我如何获得按下哪个按钮? [sender tag]给了我添加到按钮的longGestureRecognizer标签,我无法手动设置该标签。

for (...) {
    UIButton *button = [[UIButton alloc] init];
    button.tag = w + h * 3; 
    [button addTarget:self action:@selector(imageButtonPressed:) forControlEvents:UIControlEventTouchUpInside];
    UILongPressGestureRecognizer *gest = [[UILongPressGestureRecognizer alloc]
                initWithTarget:self action:@selector(imageButtonLongPress:)];
    gest.minimumPressDuration = 1;
    gest.delegate = self;

    [button addGestureRecognizer:gest];
    [gest release];

    [scrollView addSubview:button];
    [button release];
}

- (void) imageButtonLongPress:(id)sender {  
    // how to get button tag here?
}

2 个答案:

答案 0 :(得分:12)

view中有一个UIGestureRecognizer属性,它返回识别器附加到的视图。我认为这是你最好的选择。

- (void) imageButtonLongPress:(id)sender {  
    UIGestureRecognizer *recognizer = (UIGestureRecognizer*) sender;
    int tag = recognizer.view.tag;
}

答案 1 :(得分:2)

在您的操作中,您必须在手势中输入发送者,然后键入将其视图转换为按钮,然后将按钮的标记输入为 -

UILongPressGestureRecognizer *gest = (UILongPressGestureRecognizer *)sender;
UIButton *button = (UIButton*)[gest view];
NSLog(@"%d",[button tag]);