Question

我想将它们转换为整数，然后转换为百分比。例如，将0.318转换为32分，然后创建一个显示“ 32％”的列，或显示百分比标记（即0-9、10-19 ... 90-99

）的列

> exam_results_stats <- 
 tibble(exam_one = runif(1:10), exam_two = runif(1:10), exam_three =
 runif(1:10), exam_four = runif(1:10), exam_five = runif(1:10),
 exam_six = runif(1:10))

exam_results_stats[, 1:6]
   exam_one exam_two exam_three exam_four
      <dbl>    <dbl>      <dbl>     <dbl>
 1   0.318    0.225      0.432     0.915 
 2   0.0747   0.0854     0.217     0.879 
 3   0.327    0.188      0.211     0.582 
 4   0.260    0.593      0.754     0.427 
 5   0.0569   0.172      0.519     0.258 
 6   0.175    0.721      0.395     0.740 
 7   0.0530   0.414      0.924     0.919 
 8   0.486    0.670      0.491     0.894 
 9   0.566    0.891      0.786     0.868 
10   0.466    0.762      0.0480    0.0377

Answer 1

首先，您可以使用paste0和round编写函数。将其包装在format中会很有帮助，这样始终会显示正确的小数位数。然后，您可以使用lapply将此功能应用于所有列。

fxn <- function(x) {
  format(paste0(round(x * 100, 0), "%"), nsmall = 2)
}

exam_results_stats[1:6] <- lapply(exam_results_stats[1:6], fxn)

Answer 2

使用tidyverse和一些基数R

exam_results_stats <- tibble(
      exam_one = runif(1:10),  exam_two = runif(1:10), 
      exam_three = runif(1:10),  exam_four = runif(1:10), 
      exam_five = runif(1:10), exam_six = runif(1:10))

exam_results_stats %>%
  mutate_all(function(x) paste0(as.character(round(x*100, digits= 0)),"%"))

# A tibble: 10 x 6
exam_one exam_two exam_three exam_four exam_five exam_six
<chr>    <chr>    <chr>      <chr>     <chr>     <chr>   
  1 87%      34%      61%        58%       65%       96%     
  2 49%      84%      18%        26%       92%       48%     
  3 28%      33%      16%        74%       4%        5%      
  4 2%       43%      16%        21%       98%       95%     
  5 4%       30%      16%        97%       57%       58%     
  6 1%       23%      21%        20%       31%       37%

注意：您的数据现在是非数字数据，如果您希望对其进行数学运算或作图，则需要将其转换回数字数据类型

如何四舍五入到最接近的整数并转换为百分比

2 个答案: