Question

如何通过HttpClient.GetAsync方法传递请求内容？我需要根据请求内容获取数据。

[HttpGet]
public async Task<HttpResponseMessage> QuickSearch()
{
    try
    {
        using (HttpClient client = new HttpClient())
        {
            client.DefaultRequestHeaders.Accept.Clear();
            HttpResponseMessage response =await client.GetAsync("http://localhost:8080/document/quicksearch");

            if (response.IsSuccessStatusCode)
            {
                Console.Write("Success");
            }

Answer 1

我假设您的“请求内容”将是POST数据，不是吗？

如果要使用标准的表单内容发送方式，则首先必须构建内容：

var content = new FormUrlEncodedContent(new[]
            {
                new KeyValuePair<string, string>("username", "theperplexedone"),
                new KeyValuePair<string, string>("password", "mypassword123"),
            });

然后使用PostAsync提交：

var response = await client.PostAsync("http://localhost:8080/document/quicksearch", content);

Answer 2

如果要发送内容，则需要将其作为查询字符串发送（根据您的API路由）

HttpResponseMessage response =await client.GetAsync("http://localhost:8080/document/quicksearch/paramname=<dynamicName>&paramValue=<dynamicValue>");

然后在API中检查“ paramName”和“ paramValue”

Answer 3

大家好，谢谢您的评论，我找到了解决方法

[HttpGet]
        public async Task<HttpResponseMessage> QuickSearch(HttpRequestMessage Query)
        {
            Debugger.Launch();
            try
            {
                using (HttpClient client = new HttpClient())
                {
                    client.DefaultRequestHeaders.Accept.Clear();

                    Console.WriteLine(Query);
                    HttpResponseMessage response = await client.GetAsync("http://localhost:8080/document/quicksearch/"+ Query.RequestUri.Query);

                    if (response.IsSuccessStatusCode)
                    {
                        Console.Write("Success");
                    }
                    else
                    {
                        Console.Write("Failure");
                    }

                    return response;
                }
            }
            catch (Exception e)
            {

                throw e;
            }

Answer 4

如果您使用的是.NET Core，则标准的HttpClient可以直接使用。例如，要发送带有JSON正文的GET请求：

HttpClient client = ...

...

var request = new HttpRequestMessage
{
    Method = HttpMethod.Get,
    RequestUri = new Uri("some url"),
    Content = new StringContent("some json", Encoding.UTF8, ContentType.Json),
};

var response = await client.SendAsync(request).ConfigureAwait(false);
response.EnsureSuccessStatusCode();

var responseBody = await response.Content.ReadAsStringAsync().ConfigureAwait(false);

如何在C＃中使用HttpClient GetAsync方法传递请求内容

4 个答案: