Question

如何将该Curl命令传输到Java http帖子：

卷曲-不安全-XPOST -H'授权：XXXXX'-F'名称=测试名称'-F'文本=测试内容123456''http://serverhost.com/api/index.php?action=send'

谢谢大家。

我已经尝试过，但是我认为可能有更好的方法。

URL url = new URL(reqUrl);
URLConnection urlConnection = url.openConnection();
urlConnection.setDoOutput(true);
urlConnection.setRequestProperty("X-Requested-With", "Curl");
urlConnection.setRequestProperty("content-type", "application/x-www-form-urlencoded");
urlConnection.setRequestProperty("Authorization", authorization);

OutputStreamWriter out = new OutputStreamWriter(urlConnection.getOutputStream());
out.write(reqBody);
out.flush();
out.close();

Answer 1

谢谢大家。我已经解决了。代码示例失败了： URL url =新URL（urlStr）;

conn =（HttpURLConnection）url.openConnection（）;

conn.setConnectTimeout（5000）;

conn.setReadTimeout（30000）;

conn.setDoOutput（true）;

conn.setDoInput（true）;

conn.setUseCaches（false）;

conn.setRequestMethod（“ POST”）;

//高级api 如果（！TextUtils.isEmpty（authorization））{

conn.setRequestProperty("Authorization", authorization);

}

conn.setRequestProperty（“ Connection”，“保持活动”）;

conn.setRequestProperty（“ User-Agent”，

    "Mozilla/5.0 (Windows; U; Windows NT 6.1; zh-CN; rv:1.9.2.6)");

conn.setRequestProperty（“ Content-Type”，

    "multipart/form-data; boundary=" + BOUNDARY);

out = new DataOutputStream（conn.getOutputStream（））;

//文字 if（textMap！= null）{

StringBuffer strBuf = new StringBuffer();

Iterator iter = textMap.entrySet().iterator();

while (iter.hasNext()) {

    Map.Entry entry = (Map.Entry) iter.next();

    String inputName = (String) entry.getKey();

    String inputValue = (String) entry.getValue();

    if (inputValue == null) {

        continue;

    }

    strBuf.append("\r\n").append("--").append(BOUNDARY)

            .append("\r\n");

    strBuf.append("Content-Disposition: form-data; name=\""

            + inputName + "\"\r\n\r\n");

    strBuf.append(inputValue);

    logger.info(inputName + "," + inputValue);

}

out.write(strBuf.toString().getBytes());

}

卷曲转移到Java

1 个答案: