查找在指定小时内完成任务所花费的时间

Question

new = {('E_1E_2', 1.0235591568933329): [datetime.datetime(2019, 6, 25, 4, 38, 47)], 
('E_1E_2', 0.9023917716540885): [datetime.datetime(2019, 6, 25, 4, 38, 51)], 
('E_12E_2', 1.4927612857980848): [datetime.datetime(2019, 6, 25, 3, 18, 42)],
('E12_1E_2', 1.0235591568933329): [datetime.datetime(2019, 6, 25, 3, 30, 17)], 
('E_1E_2', 0.9023917716540885): [datetime.datetime(2019, 6, 25, 3, 13, 51)], 
('E_1E_2', 1.4927612857980848): [datetime.datetime(2019, 6, 25, 3, 8, 42)]}

这是我的数据输入的样子。我需要显示学生每小时完成任务所花费的时间。字典键由完成任务的学生对和他们之间的距离组成。该值由它们彼此靠近的时间戳组成。

tasktime=0
prev=datetime.datetime(1,1,1)
for i,j in new.items():
    #print(k[0],k[1])
    print(i[0],"-------------------------------------------------")
    for k,l in new.items():
        if i[0]==k[0]:
            if k[1] < 1 and len(l)==1 and j[0].hour==l[0].hour: 
                print("distance=======",k[1])
                print(l[0].hour,i[0],l)
                if (k[0],l[0]) not in sample.keys():
                    sample[k[0],l[0].hour]=0
                if prev==datetime.datetime(1,1,1):
                    prev=l[0]
                else:
                    diff=(l[0]-prev).seconds
                    tasktime=tasktime+diff
                    prev=l[0]
            elif loitime!=0 and k[1] > 1:

                print(k[0],"loitered for ",tasktime/60,"minutes")
                print("timestamp ++++++++++++++++",l[0])

我得到了他们完成全部数据所需的时间，而不是每小时。