Question

如下所示的列表，包含一些具有相同内容的元素。

例如，“ A120相对于B127”和“ B127相对于A120”自然具有相同的内容，因此在这种情况下，仅“ B127相对于A120”被视为重复内容。

我想找出哪些重复项：

a_list = [

"A120 v.s. B127",
"A125 v.s. B105",
"A122 v.s. B141",
"A150 v.s. B100",
"A147 v.s. B141",
"B127 v.s. A120",
"B100 v.s. A150"

]

for a in a_list:
    flip = a.split(' v.s. ')[1] + " v.s. " + a.split(' v.s. ')[0]
    if flip in a_list:
        print a + " is a duplicate."

但是代码标记了更多（也是第一次出现）重复项：

A120 v.s. B127 is a duplicate.
A150 v.s. B100 is a duplicate.
B127 v.s. A120 is a duplicate.
B100 v.s. A150 is a duplicate.

仅输出实际重复的方式是什么？

B127 v.s. A120 is a duplicate of A120 v.s. B127.
B100 v.s. A150 is a duplicate of A150 v.s. B100

谢谢。

Answer 1

a_list = [

"A120 v.s. B127",
"A125 v.s. B105",
"A122 v.s. B141",
"A150 v.s. B100",
"A147 v.s. B141",
"B127 v.s. A120",
"B100 v.s. A150"
]
tmp=[]
for v,i in enumerate(a_list):
    if v not in tmp:
        var =' '.join(i.split()[::-1])
        if var in a_list:
            tmp.append(a_list.index(var))

            print('{} is duplicate of {}'.format(i, var))

输出

A120 v.s. B127 is duplicate of B127 v.s. A120
A150 v.s. B100 is duplicate of B100 v.s. A150

Answer 2

带有 hashable dict键的简短解决方案：

a_list = [
    "A120 v.s. B127", "A125 v.s. B105", "A122 v.s. B141",
    "A150 v.s. B100", "A147 v.s. B141", "B127 v.s. A120",
    "B100 v.s. A150"
]

d = {}
for s in a_list:
    items = tuple(sorted(s.split()))
    if items in d:
        print(s, 'is a duplicate of', d[items])
    else:
        d[items] = s

输出：

B127 v.s. A120 is a duplicate of A120 v.s. B127
B100 v.s. A150 is a duplicate of A150 v.s. B100

Answer 3

您可以使用set进行快速查找，并使用已排序的元组来知道某项是否重复，而与顺序无关：

a_list = [
"A120 v.s. B127",
"A125 v.s. B105",
"A122 v.s. B141",
"A150 v.s. B100",
"A147 v.s. B141",
"B127 v.s. A120",
"B100 v.s. A150"
]

seen_set = set()

for line in a_list:
    pair = line.split(' v.s. ')
    sorted_pair = tuple(sorted(pair))
    if sorted_pair in seen_set:
        print('{} is a duplicate of {}'.format(' v.s. '.join(pair), ' v.s. '.join(pair[::-1])))
    seen_set.add(sorted_pair)

输出：

B127 v.s. A120 is a duplicate of A120 v.s. B127
B100 v.s. A150 is a duplicate of A150 v.s. B100

Answer 4

您在这里：

a_list = [
"A120 v.s. B127",
"A125 v.s. B105",
"A122 v.s. B141",
"A150 v.s. B100",
"A147 v.s. B141",
"B127 v.s. A120",
"B100 v.s. A150"
]

for a in a_list:
    flip = a.split(' v.s. ')[1] + " v.s. " + a.split(' v.s. ')[0]
    if flip in a_list:
        print(flip + " is a duplicate of " + a)
        del a_list[a_list.index(flip)]

输出：

B127 v.s. A120 is a duplicate of A120 v.s. B127
B100 v.s. A150 is a duplicate of A150 v.s. B100

如何在列表中找出具有相同内容的元素？

4 个答案: