在Oracle中可以在一个json_arrayagg函数下使用多个json_object函数吗？

Question

我需要创建一个数组下具有两组JSON对象的JSON。这些对象包含来自多个表的聚合数据。当我使用json_arrayagg时，出现此错误：

ORA-02000：缺少）关键字

代码应有助于解释我已经做过的事和需要的事。

SELECT JSON_OBJECT(
             'rData' VALUE JSON_ARRAYAGG(
                        JSON_OBJECT(
                            'datapoints' VALUE JSON_ARRAY(JSON_OBJECT('key' VALUE 'ENM008137Q00190',
                                                                      'value' VALUE tab3.column_6)),
                            'datatype' VALUE 'DATA_TYPE',
                            'id' VALUE tab1.column_4,
                            'key' VALUE tab3.column_1,
                            'timestamp' VALUE tab1.column_7),
                           JSON_OBJECT(
                            'id' VALUE tab1.column_4,
                            'key' VALUE tab3.column_1,
                            'timestamp' VALUE tab1.column_7,
                            'datatype' VALUE 'DATA_TYPE_2',
                            'datapoints' VALUE JSON_ARRAYAGG(JSON_OBJECT(
                                        'key' VALUE  tab5.column_8,
                                        'value' VALUE tab2.column_9))))RETURNING CLOB)
 FROM table_3 tab3, 
      table_4 tab4,
      table_2 tab2,
      table_1 tab1,
      table_5 tab5
   WHERE tab1.column_1 = tab2.column_1
   AND tab3.column_2 = tab4.column_2
   AND tab3.column_1 = tab2.column_1
   AND tab1.column_1 = tab3.column_1
   AND tab2.column_3 = tab5.column_3
   AND tab2.latenttypeid = 1
   AND tab3.column_2 = 2952326910
   AND tab2.column_10 = 8878887
   AND tab3.column_10 = 8878887
   AND tab1.date BETWEEN '19-jun-19'
                    AND '25-jun-19'
GROUP BY tab1.column_4, tab3.column_1, tab3.column_6, tab1.column_7;

这是我想要的json输出：

{                  
    "rData": [{
               "datapoints": [
                              {"key" : "ENM008137Q00190","value" : "10"}
                         ],
               "datatype": "DATA_TYPE",
               "id": "H2hnJikUKAhGVzslBVBHqg86DnwGhh8V",
               "key": "534421188",
               "timestamp": "2019-07-05T05:33:12.000Z"
                    }, 
          {
           "key":"534421188",
           "id":"H2hnJikUKAhGVzslBVBHqg86DnwGhh8V" ,
           "timestamp": "2019-07-05T05:33:12.000Z",
           "datatype": "DATA_TYPE_2",
               "datapoints": [ 
                              {"key" : "ENM008137L0001","value" : "56.0869029"},
                              {"key" : "ENM008137L0002","value" : "59.79244788"},
                              {"key" : "ENM008137L0003","value" : "73.34481183"},
                              {"key" : "ENM008137L0004","value" : "43.94661396"},
                              {"key" : "ENM008137L0005","value" : "80.71909567"},
                              {"key" : "ENM008137L0006","value" : "97.2707082"}
                    ]
                    },{
               "datapoints": [
                              {"key" : "ENM008137Q00190","value" : "9"}
                         ],
               "datatype": "DATA_TYPE",
               "id": "A1JnnNjUKAhGVzslBVBHqg86Dnw52Ccj",
               "key": "534421164",
               "timestamp": "2019-07-05T04:27:45.000Z"
                    }, 
          {
           "key":"534421164",
           "id":"A1JnnNjUKAhGVzslBVBHqg86Dnw52Ccj" ,
           "timestamp": "2019-07-05T04:27:45.000Z",
           "datatype": "DATA_TYPE_2",
               "datapoints": [ 
                              {"key" : "ENM008137L0001","value" : "88.0869029"},
                              {"key" : "ENM008137L0002","value" : "88.79244788"},
                              {"key" : "ENM008137L0003","value" : "88.34481183"},
                              {"key" : "ENM008137L0004","value" : "82.94661396"},
                              {"key" : "ENM008137L0005","value" : "99.71909567"},
                              {"key" : "ENM008137L0006","value" : "88.2707082"}
                    ]
                    }]
}

“ rData”数组下有2个json_objects，这是我想要聚合的两个数据源，但是我不确定当前函数是否可以实现。

我对代码表示歉意，我已尝试为您提供最少的信息来帮助您。当然，任何帮助总是值得赞赏的。