Question

我有一个需要onTouch滑动事件的应用程序，如Iphone。他们是

向上滑动。
向下滑动。
向左滑动。
向右滑动。

我实现了onTouch事件，如下所示。我正确地向左和向右滑动操作。但这是实现向下和向上滑动操作的正确方法。

mycode的：

    float downXValue,downYValue;

    @Override
    public boolean onTouchEvent(MotionEvent arg1) {

         // Get the action that was done on this touch event
        switch (arg1.getAction())
        {
            case MotionEvent.ACTION_DOWN:
            {
                // store the X value when the user's finger was pressed down
                downXValue = arg1.getX();
                downYValue = arg1.getY();
                break;
            }

            case MotionEvent.ACTION_UP:
            {
                // Get the X value when the user released his/her finger
                float currentX = arg1.getX();   
                float currentY=arg1.getY();

                // going backwards: pushing stuff to the right
                if (downXValue < currentX)
                {
                    Log.d(DEBUG_TAG, "Right");
                }

                // going forwards: pushing stuff to the left
                if (downXValue > currentX)
                {

                    Log.d(DEBUG_TAG, "Left");
                }
                break;
            }
        }

         //GestureListener is called here... 

        //return gestures.onTouchEvent(event);


        return true;
    }

谢谢。

Answer 1

怎么样......

if (downYValue < currentY)
{
    Log.d(DEBUG_TAG, "Down");
}

您确定在上面编写了代码吗？

修改

好的，我相信你。你要做的基本上是：

double sizeInX = Math.abs(downXValue - currentX); double sizeInY = Math.abs(downYValue - currentY); if( sizeInX > sizeInY ){ // you better swipe horizontally } else { // you better swipe vertically }

Answer 2

这是我前段时间写过的一个监听器，它可以处理两个向下的swype。我用来跟踪触摸位置的float oldPosition变量。那里有一些不需要的代码，但你会明白这个想法：

    LinearLayout tableM = (LinearLayout) findViewById (R.id.tableM);
    tableM.setOnTouchListener(new OnTouchListener () {
        public boolean onTouch(View view, MotionEvent event) {
            if (event.getAction() == android.view.MotionEvent.ACTION_DOWN) {
                oldPosition = event.getY();
                return true;
            } else
            if (event.getAction() == android.view.MotionEvent.ACTION_MOVE) {
                if (event.getY() < oldPosition) {
                    tableIndexM++;
                    if (tableIndexM > (minsecs.length - 3)) {
                        tableIndexM = 0;
                    }
                    fillTable (rowM0, rowM1, rowM2, minsecs, tableIndexM);
                }
                else if (event.getY() > oldPosition) {
                    tableIndexM--;
                    if (tableIndexM < 0) {
                        tableIndexM = minsecs.length - 3;
                    }
                    fillTable (rowM0, rowM1, rowM2, minsecs, tableIndexM);
                }
                oldPosition = event.getY();
                return true;
            }
            return false;
        }
    });

Android 0nTouch事件问题[向下轻扫]

2 个答案: