Matplotlib xtick给出了“具有多个元素的数组的真值是不明确的”

时间:2019-07-11 10:56:27

标签: python python-3.x matplotlib

我正在尝试使用matplotlib绘制一些数据。问题是当我使用plt.xtick()函数时,它会为我提供以下信息。

ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

下面的代码错误在第60行“ plt.xticks(np.array([r + barWidth for r in range(len(ener))]),xlab,rotation = 90)“

import numpy as np
from mpl_toolkits.mplot3d import axes3d
import matplotlib.pyplot as plt
import matplotlib.tri as tri
from matplotlib.ticker import MaxNLocator
import math
import os, pdb

paths=["1leo_5fpps_pwat", "1leo_5fpps_u8", "1leo_5fpps_u8_t4"]
aminoacids = {1:"Ser1", 2:"trp2", 3:"thr3", 4:"trp4", 5:"glu5", 6:"gly6", 7:"asn7", 8:"lys8", 9:"trp9", 10:"thr10", 11:"trp11", 12:"lys12"}
np.set_printoptions(suppress=True)
replica=0
f, ax = plt.subplots(3, figsize=(15,10), sharex=True)
for i in range(3):
    xf=np.random.rand(6000, 199)
    Z = np.mean(xf, axis=0)

    # set width of bar
    barWidth = 0.25

    # set height of bar
    ener = Z[1::3]
    vdw = Z[2::3]
    elec = Z[3::3]

    filtered_index=np.where(ener<25)
    ener = ener[filtered_index]
    vdw = vdw[filtered_index]
    elec = elec[filtered_index]


    ax[i].set_title(paths[i])
    # print(Z.shape, ener.shape, vdw.shape, elec.shape)
    # print("Z\n", Z)
    print("vdw\n", vdw)
    print("electrostatic\n", elec)
    print("Total\n", ener)
    print("sum\n",vdw+elec)


    # Set position of bar on X axis
    r1 = np.arange(len(ener))
    r2 = [x + barWidth for x in r1]
    r3 = [x + barWidth for x in r2]

    # Make the plot
    ax[i].bar(r1, ener, color='red', width=barWidth, edgecolor='white', label='ener')
    ax[i].bar(r2, vdw, color='green', width=barWidth, edgecolor='white', label='vdw')
    ax[i].bar(r3, elec, color='blue', width=barWidth, edgecolor='white', label='elec')
    ax[i].legend()
    xlab = np.array([(i,j) for i in range(1,13) for j in range(i+1,13)])
    xlab = xlab[filtered_index]
    xlab = np.array([[aminoacids[i], aminoacids[j]] for i,j in xlab])

pdb.set_trace()
f.suptitle('Interaction energy of Trp-zipper replica {}'.format(replica), fontsize=16)
f.text(0.5, 0.02, 'Native contacts', ha='center', fontsize=16)
f.text(0.08, 0.5, "Energy (kcal/mol)", va='center', rotation='vertical', fontsize=16)
f.subplots_adjust(hspace=0.25)
plt.xticks(np.array([r + barWidth for r in range(len(ener))]), xlab, rotation=90)
plt.setp([a.get_xticklabels() for a in f.axes[:-2]], visible=False)
plt.ion()
plt.show()
# plt.savefig("{}/plots/inter_ener_trpzip_{}.png".format(os.environ["root"], replica), bbox_inches='tight')
# plt.pause(5.0)
# plt.show()

几个月前,此方法已奏效,但现在却给我错误。我不知道为什么xtick会出现上述错误。

我已经阅读了有关该错误here的信息,并且当基于数组的某些决策语句出现此错误时,为什么xtick会产生此错误。

1 个答案:

答案 0 :(得分:3)

使用

plt.xticks(np.array([r + barWidth for r in range(len(ener))]),[ ''.join(x) for x in xlab] , rotation=90)

这里的问题是

plt.xticks(A,B) 

期望B是一个字符串列表。

但是您将B作为一个numpy数组(66 x 2)来喂食。 因此,我们将2个元素与

结合在一起
''.join()

功能,并通过列表理解遍历66。