Question

在用password_hash（）对其进行哈希处理之后，我通过PDO将密码通过表单存储到MySQL数据库中。（VARCHAR（512）字段）

$options = array(
    'cost' => 12
);
$password = password_hash($password, PASSWORD_BCRYPT, $options);

假设

$pass = "123Azerty";
//and the hash is
$hash = "$2y$12$TzpGzy1cKM81pkEr/Mn0SOVA4wn0lr.7PnKFg4SU9Hto0EUiGGRMe";

当我从数据库中获取密码并使用password_verify（）进行验证时，它始终返回false

...
...
$returnedPWD = $row['password'];
if (password_verify($pass,$returnedPWD)){
    echo "TRUE";
} else {
    echo "FALSE";
}
...
...

在这一点上，我尝试通过这种方式“手动”完成操作

$pass = "123Azerty";
$hash = "$2y$12$TzpGzy1cKM81pkEr/Mn0SOVA4wn0lr.7PnKFg4SU9Hto0EUiGGRMe";
if (password_verify($pass,$hash )){
    echo "TRUE";
} else {
    echo "FALSE";
}

它总是返回FALSE

但是

当我改变

$hash = "$2y$12$TzpGzy1cKM81pkEr/Mn0SOVA4wn0lr.7PnKFg4SU9Hto0EUiGGRMe";
// into
$hash = '$2y$12$TzpGzy1cKM81pkEr/Mn0SOVA4wn0lr.7PnKFg4SU9Hto0EUiGGRMe';

有效。因为用单引号引起来的哈希是不可解析的。根据我的理解，这意味着从数据库中获取的哈希被解释为可解析的（双重搬运），而不是根本无法工作

然后我尝试将字符串括在db int strval（）中：

...
...
$returnedPWD = strval($row['password']);
if (password_verify($pass,$returnedPWD)){
    echo "TRUE";
} else {
    echo "FALSE";
}
...
...

但是它总是返回FALSE 阅读所有与password_verify（）无法正常运行有关的帖子，对我来说，我没有提出任何有效的解决方案。

请问有什么方法可以使其正常工作吗？

预先感谢

编辑1

我确实尝试了其他设置，如PASSWORD_DEFAULT，但没有更改。我还尝试对前期数据库存储进行base64编码，然后对其进行解码。但是什么都没有改变

编辑2

我使用带有参数的PDO存储数据

 $query = "INSERT INTO `users` (username, password) VALUES (:username, :password)";

 $params = array(
            ':username' => "$username",
            ':password' => "$password" // hashed one
        );

编辑3

表结构

CREATE TABLE IF NOT EXISTS `users` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `username` varchar(50) NOT NULL,
  `password` varchar(512) NOT NULL,
  `enabled` int(1) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8mb4 AUTO_INCREMENT=13 ;


$username = trim($_POST["username"];
$password = trim($_POST["password"];

// Query to insert data
 $query = "INSERT INTO `users` (username, password, enabled) VALUES (:username, :password, 1)";

// The very original setup I did use and didn't work out
$param_password = password_hash($password, PASSWORD_DEFAULT); 

// Bind parameters
$params = array(
     ':username' => "$username",
     ':password' => "$param_password"
);
...
...
// insert into db
$sth = $sql->prepare($query);

// Call MySQL
try {
    $sth->execute($params); // Execute the Query
} catch (PDOException $e) {
    $mysql_error = 'MySQL connection failed: ' . "<br>" . $e->getMessage();
}
...
...

这里是我如何从数据库读取的基本内容

...
...
$username_login = trim($_POST["username"]);
$password_login = trim($_POST["password"]);
...
...   
$query = "SELECT * FROM `users` WHERE username = :username";
$params = array(
    ':username' => $username_login
);   

$sth = $sql->prepare($query);

try{
    $sth->execute($params);
} catch (PDOException $e)  {
    $mysql_error = 'MySQL connection failed: ' . "<br>" . $e->getMessage();
}

while ($row = $sth->fetch(PDO::FETCH_ASSOC)) {
    foreach ($row as $key => $value) {
        global $$key;
        $$key = $value;
    }
}
...
...

if (password_verify($password_login, $password) and $enabled == 1){
    // Password is correct, so start a new session
    session_start();

    // Store data in session variables
    $_SESSION["logged"] = true;
    $_SESSION["id"] = $id;
    $_SESSION["uname"] = $username_login_;                            

    // Redirect user to welcome page
    header("location: index.php");

} else {
    // Display an error message if password is not valid
    $password_login__err = "The password you entered was not valid. Or you are not enabled";
}
...
...

Answer 1

由于"$password "，您的代码无法使用-它的末尾有空格。应该是：

$query = "INSERT INTO `users` (username, password) VALUES (:username, :password)";

$params = array(
        ':username' => $username,
        ':password' => $password, // hashed one
    );

您的手动测试不起作用，因为

$hash = "$2y$12$TzpGzy1cKM81pkEr/Mn0SOVA4wn0lr.7PnKFg4SU9Hto0EUiGGRMe";

有双引号，并且将$2y，$12和$Tz...作为变量插入到空字符串中。这就是单引号起作用的原因。

根据您提供的信息，我构建了有效的示例代码：Check here

针对MySQL的password_verify（）无法正常工作

1 个答案: