Question

我正在尝试用星号替换手机号码，但文本中的最后4位数字除外，并且该文本是动态的。

Eg. John's Mobile number is 8767484343 and he is from usa.
Eg. John's Mobile number is +918767484343 and he is from india.
Eg. Sunny's Mobile number is 08767484343 and he is from india.
Eg. Rahul's Mobile number is 1800-190-2312 and he is from india.



$dynamic_var = "John's Mobile number is 8767484343 and he is from usa.";

$number_extracted = preg_match_all('!\d+!', $dynamic_var , $contact_number);

// don't know what to do next

Result will be like 
Eg. John's Mobile number is ******4343 and he is from usa.
Eg. John's Mobile number is ******4343 and he is from india.
Eg. Sunny's Mobile number is ******4343 and he is from india.
Eg. Rahul's Mobile number is ******2312 and he is from india.

Answer 1

例如，您可以直接从$ dynamic_var实现此目标：

$dynamic_var = "John's Mobile number is 8767484343 and he is from usa.";
$result = preg_replace_callback('/(?<=\s)(\d|-|\+)+(?=\d{4}\s)/U', function($matches) {
    return str_repeat("*", strlen($matches[0]));
}, $dynamic_var);

Answer 2

根据我对示例输入和所需输出的了解，您不需要preg_replace_callback()的开销。变长的超前功能使您一次可以用星号替换一个字符，只要它后面跟随4个或多个数字或连字符即可。

代码：（Demo）

$inputs = [
    "John's Mobile number is 8767484343 and he is from usa.",
    "John's Mobile number is +918767484343 and he is from india.",
    "Sunny's Mobile number is 08767484343 and he is from Pimpri-Chinchwad, india.",
    "Rahul's Mobile number is 1800-190-2312 and he is from india."
];

var_export(preg_replace('~[+\d-](?=[\d-]{4})~', '*', $inputs));

输出：

array (
  0 => 'John\'s Mobile number is ******4343 and he is from usa.',
  1 => 'John\'s Mobile number is *********4343 and he is from india.',
  2 => 'Sunny\'s Mobile number is *******4343 and he is from Pimpri-Chinchwad, india.',
  3 => 'Rahul\'s Mobile number is *********2312 and he is from india.',
)

我可以幻想一些我的代码片段无法处理的附带情况，但是每当您处理不遵循严格格式的电话号码时，您都会遇到很多难题。

Answer 3

老但有用...

<?php
    echo str_repeat('*', strlen("123456789") - 4) . substr("123456789", -4);
?>

如何在PHP中用星号代替手机号（最后4位除外）

3 个答案: