Question

如何从折线转换为矩形

query_pts = np.float32([kpts1[m.queryIdx].pt for m in good_points]).reshape(-1, 1, 2)   

train_pts = np.float32([kpts2[m.trainIdx].pt for m in good_points]).reshape(-1, 1, 2)
matrix, mask = cv2.findHomography(query_pts, train_pts, cv2.RANSAC, 5.0)
matches_mask = mask.ravel().tolist()
# Perspective transform
h, w,d = output3.shape
pts = np.float32([[0, 0], [0, h], [w, h], [w, 0]]).reshape(-1, 1, 2)
dst = cv2.perspectiveTransform(pts, matrix)
homography = cv2.polylines(frame, [np.int32(dst)], True, (255, 0, 0), 3)

Answer 1

   query_pts = np.float32([kpts1[m.queryIdx].pt for m in good_points]).reshape(-1, 1, 2)
    train_pts = np.float32([kpts2[m.trainIdx].pt for m in good_points]).reshape(-1, 1, 2)
    matrix, mask = cv2.findHomography(query_pts, train_pts, cv2.RANSAC, 5.0)
    matches_mask = mask.ravel().tolist()
    # Perspective transform
    h, w,d = output3.shape
    pts = np.float32([[0, 0], [0, h], [w, h], [w, 0]]).reshape(-1, 1, 2)
    dst = cv2.perspectiveTransform(pts, matrix)
    homography=cv2.boundingRect(dst)
    x,y,w,h = homography
    h=cv2.rectangle(fg,(x,y),(x+w,y+h),(255,0,0),3)
    cv2.imshow("Homography", h)

如何从cv2.polyline转换为cv2.rectangle？

1 个答案: