我正在AES
使用随机生成的密钥对某些文本进行加密,然后RSA
使用私钥对该密钥进行加密,以便可以将其上传到数据库。
RSA
键是使用KeyPairGenerator
中的Java
生成的,并保存为文件。使用File.ReadAllBytes()
读取密钥。
当我在Java中执行此操作时,一切正常,加密密钥始终为172 bytes
,但是当我在C#
中进行加密时,加密密钥始终为844 bytes
。我很确定使用AES
已正确加密了文本,但是RSA
加密却出了问题。
我已经检查了Java和C#中的密钥大小,它们始终匹配。从字面上看,我唯一看到的区别是RSA加密密文长度,这使数据无法使用。我相信它与填充有关,但我不知道如何解决。
Java
public String encryptText(String msg, PrivateKey key)
throws NoSuchAlgorithmException, NoSuchPaddingException,
UnsupportedEncodingException, IllegalBlockSizeException,
BadPaddingException, InvalidKeyException {
KeyGenerator generator;
this.cipher.init(Cipher.ENCRYPT_MODE, key); //cipher is initialized earlier with this.cipher = Cipher.getInstance("RSA");
try {
generator = KeyGenerator.getInstance(AES);
generator.init(128); // The AES key size in number of bits
SecretKey secKey = generator.generateKey();
Cipher aesCipher = Cipher.getInstance(AES);
aesCipher.init(Cipher.ENCRYPT_MODE, secKey);
String encText = Base64.getEncoder().encodeToString(aesCipher.doFinal(msg.getBytes("UTF-8")));
String encKey = Base64.getEncoder().encodeToString(cipher.doFinal(secKey.getEncoded()));
return "(" + encText + ")" + encKey;
} catch (NoSuchAlgorithmException | NoSuchPaddingException | InvalidKeyException | IllegalBlockSizeException | BadPaddingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
C#
public String EncryptText(byte[] privateKeyBytes, string msg)
{
try
{
RSACryptoServiceProvider RSA = new RSACryptoServiceProvider();
RSAParameters RSAKeyInfo = RSA.ExportParameters(false);
RSAKeyInfo.Modulus = privateKeyBytes;
RSA.ImportParameters(RSAKeyInfo);
RijndaelManaged aes = new RijndaelManaged();
aes.BlockSize = 128;
aes.KeySize = 128;
aes.Mode = CipherMode.ECB;
byte[] keyGenerated = aes.Key;
string keyStr = Convert.ToBase64String(keyGenerated);
byte[] keyArr = Convert.FromBase64String(keyStr);
byte[] KeyArrBytes16Value = new byte[16];
Array.Copy(keyArr, KeyArrBytes16Value, 16);
aes.Key = KeyArrBytes16Value;
ICryptoTransform encrypto = aes.CreateEncryptor();
byte[] plainTextByte = ASCIIEncoding.UTF8.GetBytes(msg);
byte[] CipherText = encrypto.TransformFinalBlock(plainTextByte, 0, plainTextByte.Length);
string encText = Convert.ToBase64String(CipherText);
string encKey = Convert.ToBase64String(RSA.Encrypt(aes.Key, true));
return "(" + encText + ")" + encKey;
}
catch (CryptographicException e)
{
Console.WriteLine("FAILED: " + e.Message);
}
return null;
}
UPDATE
感谢Henno指出问题出在我如何阅读钥匙上。我最终使用Bouncy Castle处理C#中的RSA加密。我还更改了Java代码,以使用公钥而不是私钥进行加密。
新C#
public String EncryptText(byte[] keyBytes, string msg)
{
try
{
AsymmetricKeyParameter asymmetricKeyParameter = PublicKeyFactory.CreateKey(keyBytes);
RsaKeyParameters rsaKeyParameters = (RsaKeyParameters)asymmetricKeyParameter;
RSAParameters rsaParameters = new RSAParameters();
rsaParameters.Modulus = rsaKeyParameters.Modulus.ToByteArrayUnsigned();
rsaParameters.Exponent = rsaKeyParameters.Exponent.ToByteArrayUnsigned();
RSACryptoServiceProvider rsa = new RSACryptoServiceProvider();
rsa.ImportParameters(rsaParameters);
RijndaelManaged aes = new RijndaelManaged();
aes.BlockSize = 128;
aes.KeySize = 128;
aes.Mode = CipherMode.ECB;
byte[] keyGenerated = aes.Key;
string keyStr = Convert.ToBase64String(keyGenerated);
byte[] keyArr = Convert.FromBase64String(keyStr);
byte[] KeyArrBytes16Value = new byte[16];
Array.Copy(keyArr, KeyArrBytes16Value, 16);
aes.Key = KeyArrBytes16Value;
ICryptoTransform encrypto = aes.CreateEncryptor();
byte[] plainTextByte = ASCIIEncoding.UTF8.GetBytes(msg);
byte[] CipherText = encrypto.TransformFinalBlock(plainTextByte, 0, plainTextByte.Length);
string encText = Convert.ToBase64String(CipherText);
string encKey = Convert.ToBase64String(rsa.Encrypt(aes.Key, false));
return "(" + encText + ")" + encKey;
}
catch (CryptographicException e)
{
Console.WriteLine("FAILED: " + e.Message);
}
return null;
}
答案 0 :(得分:1)
似乎出错的是,您在C#中读取了保存的“私钥文件”,大概是在变量privateKeyBytes
中读取了(但是您的代码不完整,所以我猜是这样),然后执行{{ 1}},这很奇怪,而且在密码学上也不可行。您还应该根据读入的字节在C#中实例化某种RSA类,这是我认为您在C#代码开头(前四行)尝试执行的操作。我认为应该在文档中环顾四周:
RSAKeyInfo.Modulus = privateKeyBytes
,然后从这些字节中设置RSAKeyInfo,但这不是模数。读取的字节应该是PKCS1格式或类似格式,可以是base64编码为文件格式,也可以是原始格式等。您必须研究一下Java用于将完整密钥导出到磁盘的格式。
您将从文件中读取的原始字节用作模数,这肯定会带来麻烦,并给出无效且太大的“密钥”。