Question

我不知道为什么，但是我一直保持代码在输入部分之后直接结束。

我尝试使用elif，但语法无效。

import getpass 

answer1 = getpass.getpass(prompt = "Hello Player 1, Please pick either     ROCK (1)    SCISSORS (2)   OR   PAPER (3) \n")  

answer2 = input(("Hello Player 2, Please pick either     ROCK (1)    SCISSORS (2)   OR   PAPER (3) \n")) 

Forever = 0
while Forever < 1:  
   if answer1 == 1 and answer2 == 1:  
      print('DRAW PLAY AGAIN !')  
      Forever = Forever + 1 

   if answer1 == 2 and answer2 == 2:  
      print('DRAW PLAY AGAIN !')  
      Forever = Forever + 1 

   if answer1 == 3 and answer2 == 3:  
      print('DRAW PLAY AGAIN !')  
      Forever = Forever + 1 

   if answer1 == 1 and answer2 == 2:  
      print('Player 1 wins !') 
      Forever = Forever + 1 

   if answer1 == 3 and answer2 == 1:  
      print('Player 1 wins !')  
      Forever = Forever + 1 

   if answer1 == 2 and answer2 == 3:  
      print('Player 1 wins !')  
      Forever = Forever + 1 

   if answer1 == 2 and answer2 == 1:  
      print('Player 2 wins !')  
      Forever = Forever + 1 

   if answer1 == 1 and answer2 == 3:  
      print('Player 2 wins !')  
      Forever = Forever + 1 

   if answer1 == 3 and answer2 == 2:  
      print('Player 2 wins !')  
      Forever = Forever + 1

代码也永远不会结束。

Answer 1

我不知道您为什么要用input进行一次输入，而用getpass进行一次输入，但是无论如何，您都应该将两者都更改为：

answer1 = int(getpass.getpass(...)) 
answer2 = int(input(...))

您的所有条件的格式为：answer1 == 2。 input的结果是一个字符串，因此所有这些检查都将失败，除非您将输入转换为整数。

我建议您也更改条件以使代码更简单。您实际上可能只有3个！最基本的建议：您可以执行以下操作，而不用打印3张不同的支票DRAW!：

if answer1 == answer2:
    print('DRAW PLAY AGAIN !')

最后一点：在python中，请勿使用int来检查循环...要么while True:和break when是必要的，要么仅使用Boolean变量。

While和if循环无法正常工作

1 个答案: