我在数据框中有两个属于“时间”类的字段。分别命名为Time1
和Time2
。我试图找出两者之间的时差。
CombinedFrame2$Duration <- difftime(CombinedFrame2$Time1, CombinedFrame2$Time2)
Error in as.POSIXct.numeric(CombinedFrame2$Time1) :
'origin' must be supplied
我如何让班级合作进行计算?
示例:
Time1 Time2 Duration
5:30:00 6:24:00 0:54:00
$ Time1 : POSIXlt, format: "2019-07-10 16:07:00" "2019-07-10 22:05:00" "2019-07-10 22:20:00" "2019-07-10 22:43:00" ...
$ Time2 : POSIXlt, format: "2019-07-10 22:05:00" "2019-07-10 22:20:00" "2019-07-10 22:43:00" "2019-07-10 23:15:00" ...
> dput(head(CombinedFrame2[,c("Time1", "Time2")]))
structure(list(Time1 = structure(list(sec = c(0, 0, 0, 0,
0, 0), min = c(7L, 5L, 20L, 43L, 15L, 35L), hour = c(16L, 22L,
22L, 22L, 23L, 23L), mday = c(11L, 11L, 11L, 11L, 11L, 11L),
mon = c(6L, 6L, 6L, 6L, 6L, 6L), year = c(119L, 119L, 119L,
119L, 119L, 119L), wday = c(4L, 4L, 4L, 4L, 4L, 4L), yday = c(191L,
191L, 191L, 191L, 191L, 191L), isdst = c(1L, 1L, 1L, 1L,
1L, 1L), zone = c("EDT", "EDT", "EDT", "EDT", "EDT", "EDT"
), gmtoff = c(NA_integer_, NA_integer_, NA_integer_, NA_integer_,
NA_integer_, NA_integer_)), class = c("POSIXlt", "POSIXt"
)), Time2 = structure(list(sec = c(0, 0, 0, 0, 0, 0), min = c(5L,
20L, 43L, 15L, 35L, 55L), hour = c(22L, 22L, 22L, 23L, 23L, 23L
), mday = c(11L, 11L, 11L, 11L, 11L, 11L), mon = c(6L, 6L, 6L,
6L, 6L, 6L), year = c(119L, 119L, 119L, 119L, 119L, 119L), wday = c(4L,
4L, 4L, 4L, 4L, 4L), yday = c(191L, 191L, 191L, 191L, 191L, 191L
), isdst = c(1L, 1L, 1L, 1L, 1L, 1L), zone = c("EDT", "EDT",
"EDT", "EDT", "EDT", "EDT"), gmtoff = c(NA_integer_, NA_integer_,
NA_integer_, NA_integer_, NA_integer_, NA_integer_)), class = c("POSIXlt",
"POSIXt"))), row.names = c("1:1", "1:2", "1:3", "1:4", "1:5",
"1:6"), class = "data.frame")
答案 0 :(得分:1)
您需要确保时间格式正确。请参见下面的代码。
您可以使用strptime()将时间格式化为小时,分钟和秒。
time1 <- "5:30:00"
time2 <- "6:24:00"
time1a <- strptime(time1,format="%H:%M:%S")
time2a <- strptime(time2,format="%H:%M:%S")
duration <- difftime(time2a,time1a)