即使抛出错误，Google Cloud Functions也会返回结果

Question

我有一个可调用的Google Cloud Function，它在前端调用如下：

  const register = this.$fireFunc.httpsCallable('registerForTournament');

  register(this.$route.params.id)
    .then(result => {
      console.log(result);
      this.$store.commit('tournaments/addRegistered', {
        id: this.tournament.id,
        user: { uid: this.user.uid, displayName: this.user.displayName }
      });
      this.loadingRegister = false;
    })
    .catch(error => {
      console.log('no error???');
      this.$toast.error(error);
      this.loadingRegister = false;
    });

现在该函数被调用并返回以下内容

data: { code: "cancelled", details: null }

但是，如果发生这种情况，函数应该触发错误吗？ 这是一个有关如何在函数中引发错误的示例：

if (!userObject.displayName) {
    throw new functions.https.HttpsError('cancelled', 'The Player has no display Name defined.');
}