Socket.io Swift客户端自动多次重新连接

时间:2019-07-10 18:55:38

标签: ios swift socket.io

我正在为我的应用程序使用Socket.IO-Client-Swift','〜> 13.1.0'。我已成功将我的应用程序与Socket服务器连接,但问题是,它已多次重新连接。结果,也许我无法将任何东西发送到服务器。谁能帮我这个?

这是我的代码:

SocketIOManager类:NSObject {

var locationReceiverDelegate: LocationReceiverDelegate?
static let shared = SocketIOManager()
let manager = SocketManager(socketURL: URL(string: "server-url")!, config: [.log(true), .connectParams(["token" : "token-string"])])

var socket : SocketIOClient!


override init() {
    super.init()

    socket = manager.defaultSocket
    self.connectSocket() 
}

func connectSocket() {

    socket.on(clientEvent: .connect) {data, ack in
        print("socket connected")
    }

    self.socket.on("connected") { ( dataArray, ack)  in
        print("dataArray",dataArray)
    }

    self.socket.on("error") { (data, ack) in
        print("error-->", data)
    }

    self.socket.on("location::share.error") { (data, ack) in
        print("location::share.error-->", data)
    }


    self.socket.on("location::receive") { (data, ack) in

        print("location::receive-->", data[0])

    }

}

func establishConnection() {
    print("in connect socket")
    socket.connect()
}

func disconnectSocket() {
    socket.disconnect()
    print("in disconnect socket")
}

func updateCurrentLocation(myLocation: CLLocation) {

    print(myLocation.coordinate.latitude)
    print(myLocation.coordinate.longitude)
    print(myLocation.course)


    let data : Dictionary<String,Any> = [
        "latitude": myLocation.coordinate.latitude,
        "longitude": myLocation.coordinate.latitude,
        "angle": myLocation.course
    ]
    let jsonData = try! JSONSerialization.data(withJSONObject: data)
    print(jsonData)
    let jsonString = NSString(data: jsonData, encoding: String.Encoding.utf8.rawValue)

    print((String(describing: jsonString!)))
    socket.emit("location::share", "\(String(describing: jsonString!))")

}

}

2 个答案:

答案 0 :(得分:1)

socket.emit(Your_Key, with: [Your_Data])

也许这就是您的服务器寻找数据的方式! (发出数据数组)。发出数据之前,请检查您的套接字状态。

答案 1 :(得分:0)

您是否曾在调用on事件之前尝试使用socket.off('event')?

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