Question

我想按行组织多维数组。我有一个从一个主数组创建3个数组的函数。我想以理想的列形式将这些子数组添加到新数组中。

我尝试了以下操作：

/* Note

-subArray is a data structure where i have 3 values stored at each 
index index. these are named data1, data2, data3. I'm accessing them 
with the line chamberOne.append(thing.data1). this is referenced 
from tempCount's data. 

- data structure: 
at index # 1
 -data1
 -data1
 -data3

*/


static func subArray()->[String]
{
   var temp = mainArray[0...11]
   let tempCount = Array(temp)
   var returnArr: [String] = []

   var chamberOne: [String] = []
   for thing in tempCount
   {
      chamberOne.append(thing.data1)
   }
   // i have 2 more functions built the same as chamberOne, but they 
   //are named chamberTwo and chamberThree

   //as of right now I am appending like this
   returnArr + chamberOne + chamberTwo + chamberThree
  // this brings all the data into a single dimension array. 
}

我想要一种将chamberOne，chamberTwo和chamberThree附加为列或行的方法，也可以，我只想通过附加某种形式的组织到多维空间中一维数组（chamberOne）到多维数组（returnArr）。

Answer 1

让我们假设您有两个数组，例如：

现在，我们创建一个将容纳其他数组的数组，例如：

var arr1 = ["a", "b", "c"]
var arr2 = ["1", "2", "3"]

我们现在可以将两个数组都添加到var multiDimArray = [[String]]() //Array of subarrays

multiDimArray

如果我们打印multiDimArray.append(arr1) multiDimArray.append(arr2)，我们将得到multiDimArray

如果我们需要第一个“行”，我们可以使用[["a", "b", "c"], ["1", "2", "3"]]来获得它，而multiDimArray[0]

Answer 2

如果我正确理解了您的问题，则需要[[String]]或Array of Arrays of String。我将按照以下方法修改您的功能来解决该问题：

static func subArray() -> [[String]]
{
   var temp = mainArray[0...11]
   let tempCount = Array(temp)
   var returnArr: [[String]] = []

   var chamberOne: [String] = []

   for thing in tempCount
   {
      chamberOne.append(thing.data1)
   }

   returnArr.append(chamberOne)

   //Initialise chamberTwo and chamberThree here. Then append to the 2D array.
   returnArr.append(chamberTwo)
   returnArr.append(chamberThree)

   //The returnArr now looks like this [chamberOne, chamberTwo, chamberThree]
   returnArr
}

快速将新列追加到数组

2 个答案: