Question

我将创建一个应用，该应用将从数组String [] powerBalls中使用5个数字随机提取3个数字，并将带有图片的图片切换到每个数字，然后显示该数字和图片（例如字符串“ 1”来自阵列powerballs的图像将具有名称“ o1”）。问题是，只要开关盒能找到正确的图像，我就可以在显示屏上看到数字并看到图片。然后该应用程序关闭。图像始终可见，并且应该仅以随机数出现。此代码有什么问题？我真的不知道我在做什么错，也找不到该程序的示例。

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_zufallsgenerator);
    bindViews();


    mGenerateButton.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            generateRandomNumbers();

        }
    });
}

public void generateRandomNumbers(){
    Collections.shuffle(Arrays.asList(powerBalls));

    mFirstNumber.setText(powerBalls[0]);
    mSecondNumber.setText(powerBalls[1]);
    mThirdNumber.setText(powerBalls[2]);
    mFourthNumber.setText(powerBalls[3]);
    mFifthNumber.setText(powerBalls[4]);
    mSixthNumber.setText(powerBalls[5]);

    switch (powerBalls[0]) {
        case "1":
            imageViewDice1.setImageResource(R.drawable.o1);
            imageViewDice1 = (ImageView)findViewById(R.id.image_view_dice1);
            break;
        case "2":
            imageViewDice2.setImageResource(R.drawable.o2);
            imageViewDice2 = (ImageView)findViewById(R.id.image_view_dice2);
            break;
        case "3":
            imageViewDice3.setImageResource(R.drawable.o3);
            imageViewDice3 = (ImageView)findViewById(R.id.image_view_dice3);
            break;
        case "4":
            imageViewDice4.setImageResource(R.drawable.o4);
            imageViewDice4 = (ImageView)findViewById(R.id.image_view_dice4);
            break;
        case "5":
            imageViewDice5.setImageResource(R.drawable.o5);
            imageViewDice5 = (ImageView)findViewById(R.id.image_view_dice5);
            break;
        case "6":
            imageViewDice6.setImageResource(R.drawable.o6);
            imageViewDice6 = (ImageView)findViewById(R.id.image_view_dice6);
            break;
    }
    switch (powerBalls[1]) {
        case "1":
            imageViewDice1.setImageResource(R.drawable.o1);
            imageViewDice1 = (ImageView)findViewById(R.id.image_view_dice1);
            break;
        case "2":
            imageViewDice2.setImageResource(R.drawable.o2);
            imageViewDice2 = (ImageView)findViewById(R.id.image_view_dice2);
            break;
        case "3":
            imageViewDice3.setImageResource(R.drawable.o3);
            imageViewDice3 = (ImageView)findViewById(R.id.image_view_dice3);
            break;
        case "4":   // and so on...*****

，并在java类的末尾：

public void bindViews(){
mFirstNumber = (TextView)findViewById(R.id.firstNumber);
mSecondNumber = (TextView)findViewById(R.id.secondNumber);
mThirdNumber = (TextView)findViewById(R.id.thirdNumber);
mFourthNumber = (TextView)findViewById(R.id.fourthNumber);
mFifthNumber = (TextView)findViewById(R.id.fifthNumber);
mSixthNumber = (TextView)findViewById(R.id.sixthNumber);
mPowerBall = (TextView)findViewById(R.id.powerBall);
mGenerateButton = (Button)findViewById(R.id.mgenerateButton);

带有视图的xml文件的示例：

    <TextView
    android:id="@+id/firstNumber"
    android:layout_weight="1"
    android:fontFamily="serif"
    android:textSize="24sp"
    android:padding="4dp"
    android:layout_margin="8dp"
    android:text="01"
    android:textColor="@color/startblue"
    android:layout_width="0dp"
    android:layout_height="wrap_content" />

在此先感谢您的建议和答案。干杯

图像开关盒

0 个答案: