Question

目的是每当用户单击列表中的项目时检测项目索引。

示例：

A
B
C
D
E

如果用户单击C，那么我想从list()中检索该索引号。

试图直接打印出item变量，但我在命令提示符下得到了以下输出：

[<PyQt5.QtCore.QModelIndex object at 0x0416CA70>]

import sys
from PyQt5.QtCore import *
from PyQt5.QtGui import *
from PyQt5.QtWidgets import *
from PyQt5       import QtWidgets, QtGui, QtCore
from PyQt5.QtGui import QBrush, QColor 

class Widget(QtWidgets.QWidget):
    def __init__(self):
        super().__init__()
        lay = QtWidgets.QVBoxLayout(self)

        self.listView = QtWidgets.QListView()
        self.label    = QtWidgets.QLabel("Please Select item in the QListView")
        lay.addWidget(self.listView)
        lay.addWidget(self.label)

        model = QStringListModel()
        textList = list()
        textList = ["Itemname1", "Itemname2", "Itemname3", "Itemname4", "Itemname5", "Itemname6", "Itemname7", "Itemname8"]
        model.setStringList(textList)
        self.listView.setModel(model)        

        self.listView.clicked[QtCore.QModelIndex].connect(self.on_clicked)

    def on_clicked(self, index):
        item = self.listView.selectedIndexes()
        print(item)

if __name__ == '__main__':

    app = QtWidgets.QApplication(sys.argv)
    w = Widget()
    w.show()
    sys.exit(app.exec_())

输出为[<PyQt5.QtCore.QModelIndex object at 0x0416CA70>]，但我想要整数。

Answer 1

来自documentation：

此便捷功能将返回所有已选择和视图中的非隐藏项目索引。该列表没有重复项，并且未排序。

返回QModelIndex的列表。以下将获得第一个索引：

import os
import requests
from concurrent import futures


def fetch(url, session = None):
    if session:
        r = session.get(url, timeout = 60.)
    else:
        r = reqests.get(url, timeout = 60.)
    r.raise_for_status()

    return r.content


def fetch_all(urls, session = requests.session(), threads = 8):
    with futures.ThreadPoolExecutor(max_workers = threads) as executor:
        future_to_url = {executor.submit(fetch, url, session = session): url for url in urls}
        for future in futures.as_completed(future_to_url):
            url = future_to_url[future]
            if future.exception() is None:
                yield url, future.result()
            else:
                print(f"{url} generated an exception: {future.exception()}")
                yield url, None


def get_urls(search_term, number_images = 10, token = "", session = requests.session()):
    r = requests.get(f"https://pixabay.com/api/?key={token}&q={search_term}&per_page={number_images}")
    r.raise_for_status()
    urls = [hit["webformatURL"] for hit in r.json().get("hits", [])]

    return urls


if __name__ == "__main__":
    root_dir = os.getcwd()
    session = requests.session()
    urls = get_urls("term", token = "token", session = session)

    for url, content in fetch_all(urls, session = session):
        if content is not None:
            f_dir = os.path.join(root_dir, "images")
            if not os.path.isdir(f_dir):
                os.makedirs(f_dir)
            with open(os.path.join(f_dir, os.path.basename(url)), "wb") as f:
                f.write(content)

此外，对于单个选择，您可以改用print(item[0].row())

PyQt5-索引使用QStringListModel列表的QListView

1 个答案: