Question

所以我的数据库中有多个表。我有一个 Employee 表，该表具有2个外键，其ID来自 Owner 和 Account 表，但是在以下代码中出现错误：

private static final String CREATE_TABLE_EMPLOYEE = " CREATE TABLE "
        + EMPLOYEE + "("
        + COL_EMP_ID + "INTEGER PRIMARY KEY AUTOINCREMENT,"
        + COL_EMP_LNAME + "TEXT,"
        + COL_EMP_FNAME + "TEXT,"
        + COL_EMP_IMG + "INTEGER,"
        + COL_EMP_DOB + "DATE,"
        + COL_EMP_GENDER + "TEXT,"
        + COL_EMP_PHONE + "INTEGER,"
        + FOREIGN KEY("+ COL_OWNER_ID +") REFERENCES "+ OWNER +"("+ COL_OWNER_ID +"), "
        + FOREIGN KEY("+ COL_ACCT_ID +") REFERENCES "+ ACCOUNT +"("+ COL_ACCT_ID +"));";

我也尝试过添加多个外键，但这也给我一个错误：

   ....
   + COL_OWNER_ID + "INTEGER REFERENCES" + OWNER +
   + COL_ACCT_ID + "INTEGER REFERENCES" + ACCOUNT+ ")";

您能告诉我这段代码有什么问题吗？谢谢

错误：错误：“；”预期的错误：方法声明无效；返回   键入所需的错误：非法开始键入错误：';'预期
  错误：未封闭的字符串文字错误：未封闭的字符串文字错误：    预期的

Answer 1

这是Java源代码中的语法错误，请添加一些"：

private static final String CREATE_TABLE_EMPLOYEE = " CREATE TABLE "
        + EMPLOYEE + "("
        + COL_EMP_ID + "INTEGER PRIMARY KEY AUTOINCREMENT,"
        + COL_EMP_LNAME + "TEXT,"
        + COL_EMP_FNAME + "TEXT,"
        + COL_EMP_IMG + "INTEGER,"
        + COL_EMP_DOB + "DATE,"
        + COL_EMP_GENDER + "TEXT,"
        + COL_EMP_PHONE + "INTEGER,"
        + "FOREIGN KEY("+ COL_OWNER_ID +") REFERENCES "+ OWNER +"("+ COL_OWNER_ID +"), "
        + "FOREIGN KEY("+ COL_ACCT_ID +") REFERENCES "+ ACCOUNT +"("+ COL_ACCT_ID +"));";

在SQLite数据库中添加多个外键时出错

1 个答案: