Question

当我使用带有IntelliJ Ultimate IDE的Spring Boot部署Maven项目时，出现错误500，

Wed Jul 10 15:51:03 IST 2019
There was an unexpected error (type=Internal Server Error, status=500).
could not execute statement; SQL [n/a]; nested exception is org.hibernate.exception.SQLGrammarException: could not execute statement

所以我假设这可能是由于控制器类中的Date参数错误导致的，我按如下方式传递数据，

package com.example.test3.controller;

import com.example.test3.model.employee;
import com.example.test3.repo.CustomerRepository;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RestController;

import java.util.Date;

@RestController
public class WebController {
    @Autowired
    CustomerRepository repository;

    @RequestMapping("/save")
    public String process(){
        // save a single employee
        repository.save(new employee("Jack", "ekanayakeindrajith@gmail.com", new Date(2099,9,2), "skill1"));
        return "Done";
    }
}

日期属性中有一个警告，

'Date（int，int，int）'已弃用

但是，我仍然不知道如何正确配置它。我已经在Stackoverflow中提到了类似的问题

Question1

Question2，但仍然无法解决此问题。任何帮助将不胜感激！

编辑： employee.java文件如下，

package com.example.test3.model;

import javax.persistence.*;
        import java.io.Serializable;
import java.util.Date;

@Entity
@Table(name = "employee")
public class employee implements Serializable {

    private static final long serialVersionUID = -3009157732242241606L;
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private long id;

    @Column(name = "fullname")
    private String fullname;

    @Column(name = "email")
    private String email;

    @Column(name = "dateofbirth")
    private Date dateofbirth;

    @Column(name = "skill")
    private String skill;

    protected employee() {
    }

    public employee(String fullname, String email, Date dateofbirth, String skill) {
        this.fullname = fullname;
        this.email = email;
        this.dateofbirth=dateofbirth;
        this.skill=skill;
    }

    @Override
    public String toString() {
        return String.format("employee[id=%d, fullname='%s', email='%s', dateofbirth='%s', skill='%s']", id, fullname, email, dateofbirth, skill);
    }
}

内部服务器错误，状态= 500：SpringBoot

0 个答案: