我有一个查询要保存为视图,但SSMS返回错误,指出有多个具有相同名称的列。
我试图将受影响的列重命名为别名,但是没有成功。
每个视图或函数中的列名必须唯一。视图或函数“ vwBlocks”中的列名“ codemanQuestionID”被多次指定。
create view vwBlocks as
SELECT
LUConstructionType.codemanOptionID AS LUConstruction_codemanOptionID
, LUFascias.codemanOptionID AS LUFascias_codemanOptionID
, Block.windowsID
, LUWindows.windows
, LUWindows.codemanQuestionID AS codemanQuestion_ID
, Block.externalDoorID
, LUExternalDoor.externalDoor
, LUExternalDoor.codemanOptionID as LUExternal_codemanOptionID
FROM Block LEFT OUTER JOIN
LUOwnership ON Block.ownershipID = LUOwnership.ownershipID LEFT OUTER JOIN
LULocalAuthority ON Block.localAuthorityID = LULocalAuthority.authorityTypeID LEFT OUTER JOIN
LUConstructionType ON Block.constructionTypeID = LUConstructionType.constructionTypeID LEFT OUTER JOIN
LUTV ON Block.TVID = LUTV.TVID LEFT OUTER JOIN
LUSatellite ON Block.satelliteID = LUSatellite.satelliteID LEFT OUTER JOIN
LUPlayArea ON Block.playArea = LUPlayArea.playAreaID LEFT OUTER JOIN
LURoofCovering ON Block.roofCoveringID = LURoofCovering.roofCoveringID LEFT OUTER JOIN
LUFascias ON Block.fasciasID = LUFascias.fasciasID LEFT OUTER JOIN
LUWindows ON Block.windowsID = LUWindows.windowsID LEFT OUTER JOIN
LUExternalDoor ON Block.externalDoorID = LUExternalDoor.externalDoorID LEFT OUTER JOIN
LUcontractorInfo ON Block.contractorInfoID = LUcontractorInfo.contractorID LEFT OUTER JOIN
LUagentInfo ON Block.agentInfoID = LUagentInfo.agentID LEFT OUTER JOIN
LULandlord ON Block.LandlordID = LULandlord.landlordID LEFT OUTER JOIN
LUblockStatus ON Block.blockStatusID = LUblockStatus.blockStatusID LEFT OUTER JOIN
LUPropertyGroup ON Block.propertyGroup = LUPropertyGroup.propertyGroupID LEFT OUTER JOIN
LUCommunalBoilerType ON Block.communalBoilerType = LUCommunalBoilerType.communalBoilerID LEFT OUTER JOIN
LUExternalAreaManagedBy ON Block.externalAreaManagedBy = LUExternalAreaManagedBy.managedByID LEFT OUTER JOIN
LUgasBoilerMakeModel ON Block.CommBoilerMakeModelID = LUgasBoilerMakeModel.makeModelId LEFT OUTER JOIN
LUMaintenanceResp ON Block.maintenanceRepID = LUMaintenanceResp.maintenanceRepID
有人可以推荐解决方案吗?
谢谢您的帮助。
答案 0 :(得分:0)
我没有两次看到codemanQuestionID。这是一些帮助我避免和/或解决此类问题的建议。
至少有四种方式为列添加别名:
(表达式)AS((别名))
(((alias))=(expression)
有((cte name))(((alias1),(alias2),...
FROM((子查询))AS((alias1>),(alias2,...
AS是最糟糕的IMO。它草率而混乱,特别是当您不包括AS时。我通常使用的别名样式是:
SELECT
col1 = <expression>,
col2 = <expression>,
colABC = <expression>
FROM schema.table1 AS t1
JOIN schema.table2 AS t2;
这使调试变得更加容易。